To find the area between the x-axis and the parabolic curve, take the integral of the area in which the curve is above the x-axis. function of the graph is y = 4x - x² We can tell by the function (specifically -x²) that the parabola will point downward. To find the domain in which y>0, let's find the roots (0's) of the function: 0 = 4x - x² 0 = x (4 - x) x = 0 or x = 4 Between x=0 and x=4, the curve is above the x-axis. To find the area of the graph, let's take the integral on this range:
First, take the antiderivative of 4x - x²: 2x² - (1/3) x³ Then, plug x=4 into the anti-derivative, and subtract the anti-derivative at x=0: 2(4)² - (1/3)(4³) - (0 - 0) 32 - 64/3 96/3 - 64/3 = 32/3
Our goal here is to somehow "surgically remove" the repeating part of the number, so let's start by putting the original value in a variable and messing around with it a bit.
We'll let . We want to cut the bit off completely, so let's create the scalpel that'll let us do that. If , then we can also say that . Maybe I was lying a bit: the is our real scalpel here, and is where we'll be making the cut. Mathematically, a "cut" is almost always shorthand for subtraction, so let's see what our operation (cutting off of ) leaves us with:
The operation was a success! We can now simply divide either side by 9 to find , which, when reduced by dividing the numerator and denominator by 3, gives us