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Ivanshal [37]
3 years ago
7

Drag the amounts to order them from greatest to least.

Mathematics
1 answer:
vladimir2022 [97]3 years ago
3 0
So the first thing to do is get all amounts into one common unit. I will convert them all to ft.

1.8ft.
20in = 1.666ft
56cm = 56/2.54cm = 22.05in = 1.8375ft. 

So from that, You would have 56cm -> 1.8ft -> 20in. for Greatest to Least.
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A carpenter is assigned the job of expanding a rectangular deck where the width is one-fourth the length. The length of the deck
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Let the width be W, then the length is 4W (since the width is 1/4 the length)

The area of the original deck is W*4W=4W^{2}

The dimensions of the new deck are :

length = 4W+6
width=W+2

so the area of the new deck is :

(4W+6)(W+2)= 4W^{2}+8W+6W+12= 4W^{2}+14W+12

"<span>the area of the new rectangular deck is 68 ft2 larger than the area of the original deck</span>" means that we write the equation:

4W^{2}+14W+12=68+4W^{2}

14W+12=68

14W=68-12=56

W= \frac{56}{14}= 4

the length is 4W=4*4=16    ft


Answer: width: 4, length: 16
3 0
3 years ago
A machine produces defective parts with three different probabilities depending on its state of repair. If the machine is in goo
Zina [86]

Answer:

Step-by-step explanation:

Given that a machine produces defective parts with three different probabilities depending on its state of repair.

condition             Good order         Wearing down               Needs main   Total

Prob                       0.8                            0.1                                   0.1              1

Defective               0.02                          0.1                                   0.3

Joint prob              0.016                         0.01                                0.03        0.056

a) 0.016

b) total = 0.056

c) If not defective from needs maintenance

Prob for not defective = 0.8*0.98+0.1*0.9+0.1*0.7\\=0.784+0.09+0.07\\=0.944

From machine that needs maintenance = 0.07

So reqd prob = \frac{0.07}{0.944} \\=0.0741

6 0
4 years ago
A mountain peak is 12,200 feet above sea level. The valley below is 218 feet below sea level. How far is it from the peak to the
Lady bird [3.3K]
11782 i may be wrong but i think i’m right
7 0
3 years ago
Read 2 more answers
the instructor has save $3500 and rents an apartment for $275 monthly. he believes the point 6, 1850 would be on the equation of
bazaltina [42]

Answer:Yes, he is correct

Step-by-step explanation:Plug 6 in as your x-value in the equation y=-275x+3500 and you will get y=1850

6 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

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bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
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