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3 years ago

13

Hello everyone!

1 answer:

Ivan3 years ago

3 0

After 1 year it is worth 108% of its original value
108% = 1.08
so 1.08 x 1000 = $1080

After 2nd year it is worth 92% of that $1080
92% = 0.92
so 0.92 x 1080 = $993.60

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Help with this!!plz. Asap

gizmo_the_mogwai [7]

Hey there! :D

So, we know that there are 3 z's and 3 6's.

3*z= 3z

6*3= 18

3(z+6) <== equivalent expression

3z+18 <== equivalent expression

z is by itself. It shouldn't combine. It should stay the same. 6 as a unit is separate from z.

Choices "B" and "E" are correct.

I hope this helps!
~kaikers

5 0

3 years ago

What is 77 = 4x + 57

Svetach [21]

Answer:

$x=5$

Step-by-step explanation:

$77=4x+57$

Subtract 57 from both sides:

$4x=20$

Divide both sides by 4:

$x=5$

3 0

3 years ago

Can someone help me plz Xd

stira [4]

Answer:

-2497

Step-by-step explanation:

Sn=n/2[2a+(n-1)d]

=22/2[2*-40+(22-1)d]

=11(2*-40+(21*-7)

= -2497

8 0

3 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago

8 x 10^-3 is how many times as great as 4 x 10^-6

mamaluj [8]

For this case we can rewrite the expressions as:

$3 * 10 ^ {- 3} = 0.003$

That is, we run the decimal three times to the left.

$4 * 10 ^ {- 6} = 0.000004$

That is, we run the decimal six times to the left.

So:

$0.003-0.000004 = 0.002996$

So, we have that $3 * 10 ^ {- 3}$ is 0.002996 times bigger than $4 * 10 ^ {- 6}$

Answer:

$3 * 10 ^ {- 3}$ is 0.002996 times bigger than $4 * 10 ^ {- 6}$

7 0

3 years ago

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