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Nady [450]
1 year ago
9

(Please help worth 50 points) Part A

Mathematics
1 answer:
Marina86 [1]1 year ago
6 0

x_{123} \frac{x}{y} \sqrt{x} \left \{ {{y=2} \atop {x=2}} \right. x^{2} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \int\limits^a_b {x} \, dx \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \leq \leq x_{123} \frac{x}{y}

   

                                                .                                     .                    

  •                                          

                                         

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Jeremy is taking a photography class, but he doesn't own a camera. The class organizers will rent him a camera for $6 per day. J
Mazyrski [523]
Solving the given inequality for d, we get...

6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83

Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}

The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6

8 0
3 years ago
Read 2 more answers
The question is in the picture. PLEASE HELP!!!! Thank you!!!;);)
fomenos

Answer:

19/9

Step-by-step explanation:

16/27^2/3=19/9

hope this is helpful! brainly deleted my last response for some reason

8 0
2 years ago
Rachael has a rope 5 m 32 cm long that she cut into two pieces. One piece is 249 cm long. How many centimeters long is the other
satela [25.4K]

1 m = 100 cm, so 5 m = 500 cm plus the 32 cm, so she has a rope that is 532 cm long.

532 - 249 = 283 cm

So the other piece of rope is 283 cm long.

4 0
3 years ago
Can someone please tell me how to do these problems
kow [346]
These are so easy, you won't believe it !

A negative exponent only means

       "Put all of this in the denominator, and make the exponent positive."

So    (any number)^negative power =

                     1 / (the same number)^(the same power but not negative) .

The first few problems on that sheet:

1).  5^-3  =  1 / 5^3

2).  6^-10  =  1 / 6^10

3).  (-2)^-5  =  1 / (-2)^5

Got it ?    You can do the rest of them now in about 2 minutes. 
4 0
2 years ago
The graph of y = x2 - 4x is shown on the grid.
ratelena [41]
It would be from 0 < x < 4 as the question is basically asking when is the function below the y value of 0, so below the x-axis
5 0
3 years ago
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