Answer:
Find a polynomial function whose graph passes through (6,13), (9,-11), (0,5)
1 Answers
Assuming a quadratic, we have that
y = ax^2 + bx + c
Since (0,5) is on the graph, c =5
And we have the remaining system
a(9)^2 + b(9) + 5 = -11
a(6)^2 + b(6) + 5 = 13 simplify
81a + 9b = -16 multiply through by 6 ⇒ 486a + 54b = - 96 (1)
36a + 6b = 8 multiply through by -9 ⇒ -324a -54b = -72 (2)
Add (1) and (2)
162a = -168
a = -28/27
To find b we have
36 (-28/27) + 6b = 8
-112/3 + 6b = 8
⇒ b = 68/9
The function is
y = - (28/27)x^2 + (68/9)x + 5
Answer:
3/5
Step-by-step explanation:
Convert 1/5 to a decimal which is .20.
Then multiply by 3.
Independent variables, which can be controlled or manipulated; dependent variables, which (we hope) are affected by our changes to the independent variables
Answer:
12
Step-by-step explanation:
All you is divisions as followed:
100 ÷ 8 = 12
Answer:
First option.
Third option.
Fourth option.
Step-by-step explanation:
For this exercise is important to remember that equivalent expression have the same value.
Then given the following expression provided in the exercise:
You can find equivalent expression by:
- Changing the position of 
:
(This matches with the first option)
- Solving the multiplication indicated. Then:
(This matches with the fourth option)
- Writting 
inside the parentheses:
(This matches with the third option)
