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pantera1 [17]
3 years ago
6

One light year is defined as the distance light travels in 1 year. use this information to determine how many meters there are i

n 1 light-year.
Mathematics
1 answer:
kogti [31]3 years ago
6 0
9.461*10^15 or 9,461,000,000,000,000 meters.
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What are the steps of factoring (5m-2)^2-(3m-4)^2 ?
Svetlanka [38]
We use the formula a^2 - b^2 = ( a - b )( a + b );
We have a = 5m - 2 and b = 3m - 4;
<span>(5m-2)^2-(3m-4)^2 = (5m - 2 -3m + 4) x (5m-2 + 3m - 4) = (2m + 2)(8m - 6) = 2(m +1) x 2(4m - 3) = 4(m+1)(4m-3);

</span>
6 0
3 years ago
The length of a rectangle is 3 feet longer than the width. The perimeter is 30 feet. Find the length and width of the rectangle.
barxatty [35]

Answer:

do you mean height, because then the answer would be a length of 9 and height of 6

Step-by-step explanation:

9+9=18

6+6=12

18+12=30

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3 years ago
If you place a 39-foot ladder against the top of a building and the bottom of the ladder is 33 feet from the building how tall i
Mice21 [21]

Answer:

Formulate

Based on the given conditions, formulate:

\sqrt{3 {9}^{2} }  - 3 {3}^{2}

Evaluate

Evaluate the equation/expression:

20.78461

SO THE ANSWER IS 20.78461

7 0
2 years ago
Read 2 more answers
Use complete the square to solve 5x²-7x-3=0​
Yuki888 [10]

Step-by-step explanation:

ax2 + bx + c = 0

x12 = (-b ± √D) / 2a , D = b2 - 4ac .

5x2 + 7x + 3 = 0

a = 5 , b = 7 , c = 3

D = 49 - 60 = - 11 , x1 = (-7 - i √11) / 10

x2 = (-7 + i √11) / 10

3 0
3 years ago
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A spherical balloon has a circumference of 23 cm. What is the approximate surface area of the balloon to the nearest square cent
Bad White [126]
168cm2
Let r cm be the radius of the balloon, then 
<span>2pi(r)=23=>r=23/(2pi) </span>
<span>The surface area= </span>
<span>4pi(r^2)= </span>
<span>4pi[23/2pi)]^2= </span>
<span>(23^2)/pi=168.386 cm^2 </span>
<span>approximately.</span>
7 0
3 years ago
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