Answer:
12.7311111111111 on and on
Step-by-step explanation:
Answer:
The solution set is (5,6).
Step-by-step explanation:
Given equations are:
-6x + 6y= 6 Eqn 1
-6x + 3y=-12 Eqn 2
Subtracting Eqn 2 from Eqn 1
(-6x+6y)-(-6x+3y)= 6-(-12)
-6x+6y+6x-3y=6+12
3y = 18
Dividing both sides by 3

Putting y=6 in Eqn 1
-6x+6(6)=6
-6x+36=6
-6x=6-36
-6x=-30

Hence,
The solution set is (5,6).
Answer:
x=60°
Step-by-step explanation:
Let's say the point where angle x is, be K
Because ABCD and PQRS are paralelograms,
∡PSR = ∡PQR =130°
and
∡DAB=∡DCB=70°
and by angles between parallels
∡SPQ + ∡PQR = 180°
∡SPQ + 130° = 180°
∡SPQ = 50°
by angles opposite by vertex
∡PKC = ∡BKQ = x
So in triangle PKC the sum of all angles must add up to 180°
so
∡SPQ + ∡PKC + ∡DCB = 180
50 + x + 70 = 180
x = 60