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skad [1K]
3 years ago
12

!!HURRY!!

Mathematics
2 answers:
valentina_108 [34]3 years ago
6 0
I think the answer is going to be 88
Sindrei [870]3 years ago
3 0

Answer:

Which statement is true about angles 3 and 6?

3 lines intersect to form 6 angles. Clockwise, from top left, the angles 2 (90 degrees), 1, 6, 5 (90 degrees), 4, 3.

Step-by-step explanation:

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The house numbers on Carr Memorial Avenue follow a pattern. The first four houses on the left side of the street are numbered 8,
Alinara [238K]
There would be 4 more houses on the left side of the street
3 0
3 years ago
Multiply. Simplify your answer. Write your final result as a whole number or a mixed number.
belka [17]
4³/₄ × 1¹/₂
¹⁹/₄ × ³/₂
⁵⁷/₈
7¹/₈
4 0
3 years ago
An observer in a hot air balloon sights a building that is 50 m from the balloon's launch point. The balloon has risen 165 m. Wh
Kaylis [27]
Notice the picture,
recall your SOH, CAH, TOA
\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}

you have,
opposite side, 165
adjacent side, 50
and the angle

that means, we'll need Mrs. tangent
thus 
\bf tan(\theta)=\cfrac{opposite}{adjacent}\implies tan(\theta)=\cfrac{165}{50}
\\ \quad \\
 tan^{-1}\left[ tan(\theta) \right]=tan^{-1}\left[ \cfrac{165}{50} \right]
\\ \quad \\
\theta=tan^{-1}\left[ \cfrac{165}{50}\right]
\\ \uparrow  \\
 \textit{angle of elevation}\iff\textit{angle of depression}

4 0
3 years ago
The first task of the Segment Two Honors Project is to select the Power Pill study participants’ groups and research board offic
Tatiana [17]

Answer:

Part 1: There are 4.7*10^21 ways to select 40 volunteers in subgroups of 10

Part 2: The research board can be chosen in 32760 ways

Step-by-step explanation:

Part 1:

The number of ways in which we can organized n elements into k groups with size n1, n2,...nk is calculate as:

\frac{ n!}{ n1!*n2!*...*nk! }

So, in this case we can form 4 subgroups with 10 participants each one, replacing the values of:

  • n by 40 participants
  • k by 4 groups
  • n1, n2, n3 and n4 by 10 participants of every subgroups

We get:

\frac{ 40!}{10!*10!*10!*10!} = 4.7*10^{21}

Part 2:

The number of ways in which we can choose k element for a group of n elements and the order in which they are chose matters is calculate with permutation as:

nPk = \frac{ n!}{(n-k)!}

So in this case there are 4 offices in the research board, those are director,  assistant director, quality control analyst and correspondent. Additionally this 4 offices are going to choose from a group of 5 doctors.

Therefore, replacing values of:

  • n by 15 doctors
  • k by 4 offices

We get:

\frac{ 15!}{ (15-4)! } = 32760

7 0
2 years ago
Read 2 more answers
(6^4) (6^-2) <br>I still can't find the answer.​
nikitadnepr [17]

Answer:

It would be A )6 powed by 2

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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