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3 years ago

Which of the following is the reciprocal of 5 3/7 38/7 7/38 22/3 3/22

Mathematics

2 answers:

elixir [45]3 years ago

6 0

The answer is 7/38.

jonny [76]3 years ago

4 0

Answer: 7/38

Step-by-step explanation:

You can turn 5 3/7 into an improper fraction by multiplying 5 by 7 and then adding it to the numerator to get 38/7. Then, using our knowledge that the reciprocal is the opposite of the fraction, we can flip the fraction 38/7, to get 7/38!

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svet-max [94.6K]

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Step-by-step explanation:

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1/2(larger-smaller arc)

1/2(114-36)

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5 0

2 years ago

A ball is kicked upward with an initial velocity of 32 feet per second. The ball's height, h (in feet), from the ground is model

stellarik [79]

Answer:

1. t = 0.995 s

2. h = 15.92 ft

Step-by-step explanation:

First we have to look at the following formula

Vf = Vo + gt

then we work it to clear what we want

Vo + gt = Vf

gt = Vf - Vo

t = (Vf-Vo)/g

Now we have to complete the formula with the real data

Vo = 32 ft/s as the statement says

Vf = 0 because when it reaches its maximum point it will stop before starting to lower

g = -32,16 ft/s² it is a known constant, that we use it with the negative sign because it is in the opposite direction to ours

t = (0 ft/s - 32 ft/s) / -32,16 ft/s²

we solve and ...

t = 0.995 s

Now we will implement this result in the following formula to get the height at that time

h = (Vo - Vf) *t /2

h = (32 ft/s - 0 ft/s) * 0.995 s / 2

h = 32 ft/s * 0.995 s/2

h = 31.84 ft / 2

h = 15.92 ft

4 0

2 years ago

15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.

Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = $30C5 = \frac{30 !}{(30-5)!5!} \\$

$30C5 = 142506$ ways

Number of ways of selecting 5 good bulbs from 26 bulbs = $26C5 = \frac{26 !}{(26-5)!5!} \\$

$26C5 = 65780$ ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = $\frac{26C4 * 4C1}{30C5}$

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) = $\frac{26C3 * 4C2}{30C5}$

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) + Pr(2 defective) + Pr(3 defective) + Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) = $\frac{26C2 * 4C3}{30C5}$

Pr(3 defective) = 0.009

Pr(4 defective) = $\frac{26C1 * 4C4}{30C5}$

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0

3 years ago

Tell me the answer to 10 times 2000 equal blank thousand equal blank

timofeeve [1]

10x2000= 20,000
2000
X 10
--------
0000
20000

5 0

2 years ago

Please help me I need this answer

alexandr402 [8]

Answer:

Then answer is 10.

Step-by-step explanation:

9 would cover 1,800 square feet so 925 square feet would be left so you should buy 10 cans.

8 0

2 years ago

Read 2 more answers