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3 years ago

Jenny, Keith, and Joanna participated in a mini-

Mathematics

1 answer:

Elan Coil [88]3 years ago

4 0

Answer:

Jenny 1.75 miles, Keith 4.75 miles, Jonna 9.5 miles

Step-by-step explanation:

Distance per person:

Jenny - x, Keith - y, Joanna - z

Equation as per given:

y = x + 3
z = 2y = 2(x + 3)
x + y + z = 16

Substitute and solve for x:

x + (x + 3) + 2(x + 3) = 16
2x + 3 + 2x + 6 = 16
4x = 7
x = 7/4 = 1.75

Then

y = 1.75 + 3 = 4.75
z = 4.75*2 = 9.5

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D. The sum of two numbers is 30 and the difference of these numbers is 6.

Marianna [84]

The answer is 18 and 12

5 0

4 years ago

Ben sells greeting cards for $5 each in his online store. He also charges $1.99 for shipping. The total cost, y, of an order fro

laila [671]

5 would be the dependent variable because the number 5 depends on how many greeting cards are bought.

7 0

3 years ago

The line x − y = 2 is on a coordinate plane and contains EF, which is one side of square EFGH. What is the slope of the line tha

Alborosie

Answer:

The slope of FG is -1

Step-by-step explanation:

Given

Square EFGH

EF: $x - y = 2$

Required

Determine the slope of FG

First, we calculate the slope of EF

$x - y = 2$

Make y the subject

$-y = 2 - x$

$y = x -2$

The general equation has the form: $y = mx + b$

Where

$m = slope$

Compare $y = mx + b$ to $y = x -2$

$m = 1$

From the name of the square EFGH, we can conclude that EF and FG are perpendicular

The relationship between perpendicular lines is:

$m_2 = -\frac{1}{m_1}$

Where

$m_1 = m = 1$ -- Slope of EF

and

m2 = slope of FG

Substitute 1 for m1 in $m_2 = -\frac{1}{m_1}$

$m_2 = -\frac{1}{1}$

$m_2 = -1\\$

Hence, the slope of FG is -1

3 0

3 years ago

Compute the correlation coefficient for the data set. (2,19), (3,22), (4,26), (5,20), (6,35), (7,30), (9,40), (10,42), (11,35)

lakkis [162]

Answer:

The correlation coefficient of the data is 0.8679.

Step-by-step explanation:

The formula to compute the correlation coefficient is:

$r(X,Y)=\frac{n\cdot \sum XY-\sum X\cdot \sum Y}{\sqrt{n\cdot\sum X^{2}-(\sum X)^{2}}\times \sqrt{n\cdot\sum Y^{2}-(\sum Y)^{2}}}$

From the data provided compute the values of ∑ XY, ∑ X, ∑ Y, ∑ X² and ∑ Y².

The values are computed in the table below.

Compute the correlation coefficient as follows:

$r(X,Y)=\frac{n\cdot \sum XY-\sum X\cdot \sum Y}{\sqrt{n\cdot\sum X^{2}-(\sum X)^{2}}\times \sqrt{n\cdot\sum Y^{2}-(\sum Y)^{2}}}$

$=\frac{(9\times 1893)-(57\times 269)}{\sqrt{(9\times 441)-(57)^{2}}\times \sqrt{(9\times 8635)-(269)^{2}}}\\\\=\frac{1704}{\sqrt{720\times 5354}}\\\\=0.86788895\\\\\approx 0.8679$

Thus, the correlation coefficient of the data is 0.8679.

4 0

3 years ago

The average of 12 numbers is 153 what is the sum of the 12 numbers

Fantom [35]

Answer:

Sum is 1836.

Step-by-step explanation:

As we know,

average= sum/total numbers

153=sum/12

153*12=sum

sum=1836

4 0

3 years ago