Answer:
a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O
b. The conversion factor that Jacob did, was wrong.
Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:
9.45 mol . 102 g / 1 mol = 963.9 g
Explanation:
Al₂O₃ → Aluminum oxide
We determine the molar mass:
Molar mass Al . 2 + Molar mass O . 3
27 g/mol . 2 + 16 g/mol . 3 = 102 g/mol
a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O
b. The conversion factor that Jacob did, was wrong.
Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:
9.45 mol . 102 g / 1 mol = 963.9 g
