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3 years ago

Please help with this chemistry question, image attached.

Chemistry

1 answer:

Alexeev081 [22]3 years ago

7 0

Answer:

a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O

b. The conversion factor that Jacob did, was wrong.

Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:

9.45 mol . 102 g / 1 mol = 963.9 g

Explanation:

Al₂O₃ → Aluminum oxide

We determine the molar mass:

Molar mass Al . 2 + Molar mass O . 3

27 g/mol . 2 + 16 g/mol . 3 = 102 g/mol

a. Sally did not take account the atoms of the compounds, because she only summed Al + O and in the oxide, we have 2 mol of Al and 3 mol of O

b. The conversion factor that Jacob did, was wrong.

Moles must be divided by moles, so they can be cancelled. The correct conversion factor is:

9.45 mol . 102 g / 1 mol = 963.9 g

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Read 2 more answers

Given the following chemical equation, if 50.1 grams of silicon dioxide is heated with excess carbon and 32.3 grams of silicon c

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Answer:

97%.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

SiO2 (s) + 3C (s) —> SiC(s) + 2CO(g)

Next, we shall determine the mass of SO2 that reacted and the mass of SiC produced from the balanced equation. This is illustrated below:

Molar mass of SiO2 = 28 + (16x2) = 60 g/mol

Mass of SO2 from the balanced equation = 1 x 60 = 60 g

Molar mass of SiC = 28 + 12 = 40 g/mol

Mass of SiC from the balanced equation = 1 x 40 = 40 g.

From the balanced equation above,

60 g of SiO2 reacted to produce 40 g of SiC.

Next, we shall determine the theoretical yield of SiC. This can be obtained as follow:

From the balanced equation above,

60 g of SiO2 reacted to produce 40 g of SiC.

Therefore, 50.1 g of SiO2 will react to produce = (50.1 x 40)/60 = 33.4 g of SiC.

Therefore, the theoretical yield of SiC is 33.4 g

Finally, we shall determine the percentage yield of SiC as follow:

Actual yield of SiC = 32.3 g

Theoretical yield of SiC = 33.4 g

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 32.3/33.4 x 100

Percentage yield = 96.7 ≈ 97%

Therefore, the percentage yield of the reaction is 97%.

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