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Kisachek [45]
3 years ago
8

Solve: (a)(9a + 4) = 0.

Mathematics
2 answers:
erastovalidia [21]3 years ago
7 0

Answer:

10a+4

Step-by-step explanation:

10a+4

that's it

Monica [59]3 years ago
4 0

Answer:

a = -4/9

Step-by-step explanation:

(9a + 4) = 0

Subtract 4 from each side

9a + 4-4 = 0-4

9a = -4

Divide each side by 9

9a/9 = -4/9

a = -4/9

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8x2 - 6x + 3 – 2x – 10x?
Marina CMI [18]

Answer:

8x^{2} + 3 + -6x

Step-by-step explanation:

First we need to find the like terms so that we could add them. In this case the like terms are,

1. 6x , -2x , -10x

So, these are the only terms that we can add in this expression.

Hence,

=> 8x^{2} + 3 + (6x - 2x - 10x)

=> 8x^{2} + 3 + -6x

And this is as simple as this expression can go until we find the value of "x" which is not yet told.

Hope my answer helped.

4 0
3 years ago
Read 2 more answers
7 watermelons cost $8.96. How many full watermelons can you buy for $20.
fenix001 [56]

Answer:

If each Watermelon costs $8.96, you can buy two

5 0
3 years ago
Find the GCF of 14 and 15. GCF=
AnnZ [28]

Answer:

1

Step-by-step explanation:

14 - 2 x 7

15 - 3 x 5

GCF of 14 and 15: 1

3 0
2 years ago
Read 2 more answers
At 9:00 a.m. marsha found a parking meter that still had 5 minute until it expired. She quickly put a quarter, 1 dime, and a nic
LUCKY_DIMON [66]
1 quarter + 1 dime + 1 nickel = 25¢ + 10¢ + 5¢ = 40¢

Each 5<span>¢ buys 15 minutes.  How many ' 5</span>¢ ' are in 40<span>¢</span> ?

40/5 = 8 of them.  So the (quarter+dime+nickel) can buy 8 x 15 minutes = 2 hours.

Starting at 9:00 AM, the meter had 5 minutes left on it, and Marsha bought
another 2 hours.  So now the meter is good until 2 hours and 5 minutes
after 9:00 AM . . . . . 11:05 AM.






8 0
3 years ago
1) Fairview and Abbots Rise are 5 in apart on a map that has a scale of 1 in : 18 mi. How far apart are the real cities? 2) A pa
erik [133]

Answer:

1) 90 mi

2) 4 inch

Step-by-step explanation:

1)

Given that the distance between Fairview and Abbots Rise on the map = 5 in

Scale of the map = 1 in: 18 mi

i.e. 1 inch on map is equivalent to an actual distance equal to 18 mi between the cities.

Given that the map has a distance of 5 inches.

Therefore, the actual distance between the cities = 5 \times 18 = <em>90 mi</em>

<em></em>

2) A particular satellite is 12 ft wide.

Model's scale = 1 in : 3 ft

i.e. 1 inch on map is equivalent to actual distance of 3 ft.

OR

3 ft of actual distance = 1 in on map

1 ft of actual distance = \frac{1}{3} in on map

12 ft of actual distance = \frac{1}{3}\times 12 = \bold{4\ inch}

4 0
2 years ago
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