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Llana [10]
3 years ago
14

The volume of a cube is 343 cubic yards what is the length of the cube

Mathematics
1 answer:
enyata [817]3 years ago
3 0
Volume= length^3\\\\ 343=length^3\ \ \ | make\ cube \ root\\\\length=\sqrt[3]{343}\\\\ length=7yards\\\\ Length\ of\ cube\ is \ 7\ yards.
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11. In circle H, if mDHG = (11x - 36)* and mGHF = (x + 12), find mDG.
Dima020 [189]

mˆDG=151∘∘

An arc’s length means the same commonsense thing length always means — you know, like the length of a piece of string

4 0
3 years ago
The ratio of boys to girls in a room is 4:9.<br> There are a total of 39 people in the room.
Mumz [18]

12 boys and 27 girls

1) Add 4 to 9. 13

2) 39 divided by 13 is 3

3)Multiple 3 to 4 boys and 9 girls. 3x4 is 12 boys, 3x9 is 27 girls

Hope this helps!

4 0
3 years ago
Read 2 more answers
En la tienda de mascotas "Animalo-T", se desea elevar un elefante de 2,900 kg utilizando una elevadora hidráulica de plato grand
Korvikt [17]

Answer:

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

Step-by-step explanation:

Por el Principio de Pascal se conoce que el esfuerzo experimentado por el elefante es igual a la presión ejercida por el plato pequeño. Es decir:

\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} (1)

Donde:

F_{1} - Fuerza experimentada por el elefante, medida en newtons.

F_{2} - Fuerza aplicada sobre el plato pequeño, medida en newtons.

A_{1} - Área del plato grande, medida en metros cuadrados.

A_{2} - Área del plato pequeño, medida en metros cuadrados.

La fuerza aplicada sobre el plato pequeño es:

F_{2} = \left(\frac{A_{2}}{A_{1}} \right)\cdot F_{1}

La fuerza experimentada por el elefante es su propio peso. Por otra parte, el área del plato es directamente proporcional al cuadrado de su diámetro. Es decir:

F_{2} = \left(\frac{D_{2}}{D_{1}} \right)^{2}\cdot m\cdot g (2)

Donde:

D_{1} - Diámetro del plato grande, medido en centímetros.

D_{2} - Diámetro del plato pequeño, medido en centímetros.

m - Masa del elefante, medida en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que D_{1} = 0.75\,m, D_{2} = 0.13\,m, m = 2900\,kg y g = 9.807\,\frac{m}{s^{2}}, entonces la fuerza a aplicar al émbolo pequeño es:

F_{2} = \left(\frac{0.13\,m}{0.75\,m} \right)^{2}\cdot (2900\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F_{2} = 854.473\,N

Se requiere una fuerza de 854.473 newtons sobre el émbolo pequeño.

3 0
3 years ago
What is the area of this polygon in square units ?
Maru [420]

Answer:

9 units²

Step-by-step explanation:

This is a trapezium.

The length of the two parallel lines (on top and bottom) are 5 units and 1 units.

The height of the trapezium is 3 units. Using these information, we can apply the formula for area of trapezium to find the answer.

Area = 1/2 (5 + 1) x 3 = 9 units²

7 0
3 years ago
Find radius of the sphere from the following volume
nordsb [41]
Can you send a picture by chance?
3 0
2 years ago
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