Question

Subtract a4 + 40²62 — 264 from –3a4 + 5a62 +264.

Answer 1

Note: Although your statement sounds a little ambiguous, but I am assuming that you want to subtract $a^4\:+\:40^2\:\cdot 62-\:264$ from $-3a^4\:+\:5a^{62}\:+264$. Anyways, even if you may have a slightly different expressions, but the procedure remains the same. So it would anyways help you understand the concept.

Answer:

$-3a^4+5a^{62}+264-\left(a^4+40^2\cdot \:62-264\right)=5a^{62}-4a^4-98672$

Step-by-step explanation:

Given the expression

$a^4\:+\:40^2\:\cdot 62-\:264$

which have to be subtracted from $-3a^4\:+\:5a^{62}\:+264$

so

$-3a^4+5a^{62}+264-\left(a^4+40^2\cdot \:62-264\right)$

$=-3a^4+5a^{62}+264-\left(a^4+98936\right)$   ∵ $-\left(a^4+40^2\cdot \:62-264\right)=-\left(a^4+98936\right)$

$=-3a^4+5a^{62}+264-a^4-98936$

$\mathrm{Group\:like\:terms}$

$=5a^{62}-3a^4-a^4+264-98936$

$\mathrm{Add\:similar\:elements:}\:-3a^4-a^4=-4a^4$

$=5a^{62}-4a^4+264-98936$

$=5a^{62}-4a^4-98672$

Therefore,

$-3a^4+5a^{62}+264-\left(a^4+40^2\cdot \:62-264\right)=5a^{62}-4a^4-98672$