Answer:
In Python:
def split(A):
L=[]; G=[]
for i in range(1,len(A)):
if (A[i] != A[0] and A[i] < A[0]):
L.append(A[i])
if (A[i] != A[0] and A[i] > A[0]):
G.append(A[i])
return L, G
Explanation:
This defines the function
def split(A):
This initializes the L and G lists
L=[]; G=[]
This iterates through the original list A
for i in range(1,len(A)):
This populates list L using the stated condition
<em> if (A[i] != A[0] and A[i] < A[0]):</em>
<em> L.append(A[i])</em>
This populates list G using the stated condition
<em> if (A[i] != A[0] and A[i] > A[0]):</em>
<em> G.append(A[i])</em>
This returns the two lists L and G
return L, G
Answer:
The answer is "Option b".
Explanation:
In the given code, a static method "inCommon" is declared, that accepts two array lists in its parameter, and inside the method two for loop is used, in which a conditional statement used, that checks element of array list a is equal to the element of array list b. If the condition is true it will return the value true, and if the condition is not true, it will return a false value. In this, the second loop is not used because j>0 so will never check the element of the first element.
I think the answer is true
Answer: Informal bench-marking
Explanation:
Informal bench-marking is defined as unconscious comparison of one's own behavior, skills, values etc with other and learning from them to improve. This leaning can be found in work-place, home, school etc.
- According to the question, Myles is using informal bench-marking through studying other stores complaint handling style and reduction technique so that he can learn from it.
- Other options are incorrect because designing analysis,outcome analysis, issue analysis and processing of complaining ta re not the comparison that unconsciously done by person .
- Thus, the correct option is informal bench- marking.
It should be compiled. It won't work if it's not compiled.
