Answer:
0.6 moles of Fe
Explanation:
Given data:
Number of atoms of Fe = 3.612×10²³
Number of moles = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
From atoms to mole:
3.612×10²³ atoms of Fe × 1 mole / 6.022 × 10²³ atoms
0.6 moles of Fe
This easy bro there is only one answer Gravity
but here my advance word
Sometimes the gravity of big objects would capture smaller ones in orbit. This could be one way the planet acquired the moon
Atomic mass is the number that you get when the protons and neutrons in the nucleus are added together atomic number is the number of protons in the nucleus
Convert all of the units from centimeters to meters by moving the decimal point over to the left two digits.
0.15 m x 0.06 m x 0.12 m
Volume = length x width x height
= 0.15 x 0.06 x 0.12 = 0.00108 m^3
Ionic bonds are formed when there is complete transfer of valence electrons between two atoms.
Electronegativity tells the trend of an atom to atract electrons.
You should search for the complete set of rules that indicate whether an ionic or covalent bond happens.
There are two relevant rules to state if whether an ionic bond will happen:
- When the difference of electronegativities between the two atoms is greater than 2.0, then the bond is ionic.
- When the difference is between 1.6 and 2.0, the bond is ionic if one of the elements is a metal.
You need to list the electronegativities of the five elements (there are tables with this information)
Element electronegativity
Cu: 1.9
H: 2.2
Cl 3.16
I: 2.66
S: 2.58
Differences:
Cu / S: 2.58 - 1.9 = 0.68
H / S: 2.58 - 2.2 = 0.38
Cl / S: 3.16 - 2.58 =0.58
I / S: 2.66 - 2.58 = 0.08
Those differences are too low to consider that the bond is ionic.
Then the answer is that none of those atoms forms an ionic bond with sulfur.
