All categories

2 years ago

Compounds form as a result of chemical

Chemistry

1 answer:

vampirchik [111]2 years ago

7 0

Answer:A compound is formed as a result of chemical reaction, between the constituent elements

Explanation:

A compound is formed as a result of chemical reaction, between the constituent elements. The properties of compound are different from the properties of the elements from which it is formed. Ex. Compounds can be further divided into three classes : acids, bases and salts, on the basis of their properties.

You might be interested in

Can a mini fridge still be used if you break the freezer

Romashka [77]

The fridge part can, just not the freezer, I think.

8 0

3 years ago

Why are plastic building blocks good for building molecules

9966 [12]

Plastic building blocks are good for building molecules because of some useful properties which they possess. For instance, plastic are flexible, they can be easily manipulated and can be made into any shape, size and combination. They can also be produced using different colors. Because of these features, they can be used to build and to explain how molecules behave.

5 0

2 years ago

Read 2 more answers

A student dissolves of urea in of a solvent with a density of . The student notices that the volume of the solvent does not chan

Dimas [21]

The question incomplete , the complete question is:

A student dissolves of 18.0 g urea in 200.0 mL of a solvent with a density of 0.95 g/mL . The student notices that the volume of the solvent does not change when the urea dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to significant digits.

Answer:

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

Explanation:

Moles of urea = $\frac{18.0 g}{60 g/mol}=0.3 mol$

Volume of the solution = 200.0 mL = 0.2 L (1 mL = 0.001 L)

$Molarity(M)=\frac{\text{Moles of compound}}{\text{Volume of solution in L}}$

Molarity of the urea solution ;

$M=\frac{0.3 mol}{0.200 L}=1.50 M$

Mass of solvent = m

Volume of solvent = V = 200.0 mL

Density of the urea = d = 0.95 g/mL

$m=d\times V=0.95 g/mL\times 200.0 mL=190 g$

$m = 190 g = 190 \times 0.001 kg = 0.19 kg$

(1 g = 0.001 kg)

Molality of the urea solution ;

$Molality(m)=\frac{\text{Moles of compound}}{\text{Mass of solvent in kg}}$

$m=\frac{0.3 mol}{0.19 kg}=1.58 m$

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

7 0

2 years ago

Picture has the question

xenn [34]

Answer:I believe it is 5

Explanation:

8 0

2 years ago

Read 2 more answers

Using the following equation: 3H2SO4+ 2Fe -> Fe2(SO4)3+ 3H2

Mariana [72]

Answer:

H₂SO₄

Explanation:

Given data:

Number of moles of H₂SO₄ = 15 mol

Number of moles of Fe = 13 mol

Which reactant is limiting reactant = ?

Solution:

Chemical equation:

3H₂SO₄ + 2Fe → Fe₂(SO₄)₃ + 3H₂

now we will compare the moles reactant with product.

H₂SO₄ : Fe₂(SO₄)₃

3 : 1

15 : 1/3×15 = 5

H₂SO₄ : H₂

3 : 3

15 : 15

Fe : Fe₂(SO₄)₃

2 : 1

13 : 1/2×13 = 6.5

Fe : H₂

2 : 3

13 : 3/2×13 = 19.5

Number of moles of product formed by H₂SO₄ are less thus it will act as limiting reactant.

8 0

2 years ago