In NaMnO₄, Mn has the highest oxidation number.
The question is incomplete, the complete question is;
Which of the following species contains manganese with the highest oxidation number?
A) Mn
B) MnF₂
C) Mn₃(PO₄)₂
D) MnCl₄
E) NaMnO₄
In order to ascertain the specie that contains manganese with the highest oxidation number, we must calculate the oxidation number of manganese in each of the species one after the other.
1) For Mn, the oxidation number of Mn is zero because the atom is uncombined.
2) For MnF₂;
Mn has an oxidation number of +2
3) For Mn₃(PO₄)₂
Mn has an oxidation number of +2
4) For MnCl₄
Mn has an oxidation number of +4
5) For NaMnO₄
Mn has an oxidation number of +7
Hence in NaMnO₄, Mn has the highest oxidation number.
Learn more: brainly.com/question/10079361
Answer:
the last one
Explanation:
one atom had a higher electronegativity than the atom it is sharing with.
Energy is released as a bond is formed
Answer:
Independent variables are ones that can be controlled and dependent variables are results of these changes. So, in question a, an independent variable is amount of a released energy, in these case in form of heat. We reduced that amount and as a result we get a dependent variable as high temperature of chocolate for longer time, so we changed time of a heat releasing from chocolate. In question b, an independent variable is temperature of water, and a dependent variable is amount of produced oxygen. In question c, an independent variable is an intensity of exercise. When we change the intensity of exercise, as a results, breathing rate is changed, which is dependent variable.
Explanation:
