Answer:
6.2846
Explanation:
Given that:-
Concentrations at equilibrium :-
![[CH_4]=0.126\ M](https://tex.z-dn.net/?f=%5BCH_4%5D%3D0.126%5C%20M)
![[H_2O]= 0.242\ M](https://tex.z-dn.net/?f=%5BH_2O%5D%3D%200.242%5C%20M)
![[CO]= 0.126\ M](https://tex.z-dn.net/?f=%5BCO%5D%3D%200.126%5C%20M)
![[H_2]= 1.15\ M](https://tex.z-dn.net/?f=%5BH_2%5D%3D%201.15%5C%20M)
The equilibrium reaction is:-
The expression for equilibrium constant is:
![K_{c}=\frac {\left [ H_2 \right ]^3\left [ CO \right ]}{\left [ CH_4 \right ]\left [ H_2O \right ]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%20%7B%5Cleft%20%5B%20H_2%20%5Cright%20%5D%5E3%5Cleft%20%5B%20CO%20%5Cright%20%5D%7D%7B%5Cleft%20%5B%20CH_4%20%5Cright%20%5D%5Cleft%20%5B%20H_2O%20%5Cright%20%5D%7D)
Applying the values as:-
<u>The equilibrium constant for the reaction is:- 6.2846</u>
The balanced equation for the reaction between KOH and HBr is as follows;
KOH + HBr --> KBr + H₂O
stoichiometry of KOH to HBr is 1:1
number of KOH moles reacted - 0.25 mol/L x 0.015 L = 0.00375 mol
according to molar ration
number of KOH moles reacted = number of HBr moles reacted
number of HBr moles reacted - 0.00375 mol
if 12 mL of HBr contains - 0.00375 mol
then 1000 mL of HBr contains - 0.00375 mol / 12 mL x 1000 mL = 0.313 mol
therefore molarity of HBr is 0.313 M
Answer:
236.9g
Explanation:
Given parameters:
Volume of gas = 81.3L
Pressure of gas = 204kPa
temperature of gas = 95°C
Unknown:
Mass of carbondioxide gas = ?
Solution:
To solve this problem, the ideal gas law will be well suited. The ideal gas law is a fusion of Boyle's law, Charles's law and Avogadro's law.
Mathematically, it is expressed as;
PV = nRT
the unknown here is n which is the number of moles;
P is the pressure, V is the volume, R is the gas constant and T is the temperature.
convert pressure into atm
101.325KPa = 1atm
204 kPa = 
= 2atm
Convert temperature to Kelvin; 95 + 273 = 368K
2 x 81.3 = n x 0.082 x 368
n = 
= 5.38moles
Since the unknown is mass;
Mass = number of moles x molar mass
Molar mass of carbon dioxide = 12 + 2(16) = 44g/mol
Mass = 5.38 x 44 = 236.9g
Change occurs in the density of the gummy bear to change if we soaked it in isopropanol.
<h3>Effects on density by soaking isopropanol</h3>
We expect the density of the gummy bear to change if we soaked it in isopropanol because the gummy bear absorb the liquid which increase its density due to increasing weight of the gummy bear.
If a substance gains weight then its density also increases and we know that when the gummy bear was soaked in the isopropanol then its weight increases so its density is also changes so we can conclude that change occurs in the density of the gummy bear to change if we soaked it in isopropanol.
Learn more about density here: brainly.com/question/1354972
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