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2 years ago

No link or Files plz i need help with this one i been stuck on it for a long time

Chemistry

2 answers:

mina [271]2 years ago

5 0

Answer:

The particles in a solid are tightly packed and locked in place. Although we cannot see it or feel it, the particles are moving or vibrating in place.

kupik [55]2 years ago

4 0

Answer:

molecules in a solid are tightly packed together and vibrate about their fixed positions.

Explanation:

there is very little movement between molecules in a solid since there is not much space between the molecules, hence the slight vibrations.

i hope this helps! :D

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Blank is most if the compounds that make up living things?

Margarita [4]

Answer:

carbon

Explanation:

Carbon forms compounds that make up about 18 percent of all the matter in living things. The processes by which organisms consume carbon and return it to their surroundings constitute the carbon cycle.

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2 years ago

What is the density of an object if its mass is 10 g and a volume of 2 mL?

Lilit [14]

Hi there! Let's solve this problem shall we!

⠀Volume = 10g

Mass = 2 mL

In this specific problem, they are asking us to find the density of the object. So, using the information given to us (volume and mass), let's solve the problem!

Now, if you remember, D = M ÷ V

So, let's fill in the blanks!

D = Our unknown value

M = 2mL

V = 10g

Here is the filled out formula:

D = M ÷ V

D = 2mL ÷ 10g

D = 5 g/mL

*Make sure you put the units for your final solution!*

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1 year ago

A trophic level is a number that tells you the position an organism occupies in a food chain or food pyramid.

svet-max [94.6K]

Answer:

true

Explanation:

8 0

2 years ago

When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin

loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=8.2^0C$ = Depression in freezing point

$K_f$ = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality = $\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9$

$8.2^0C=1\times K_f\times 1.9$

$K_f=4.32^0C/m$

Now Depression in freezing point for sodium chloride is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=20.0^0C$ = Depression in freezing point

$K_f$ = freezing point constant

m= molality = $\frac{136g\times 1000}{950g\times 58.5g/mol}=2.45$

$20.0^0C=i\times 4.32^0C\times 2.45$

$i=1.9$

Thus vant hoff factor for sodium chloride in X is 1.9

3 0

2 years ago

What is the enthalpy of combustion when 1 mol C6H6(g) completely reacts with oxygen? 2C6H6(g) 15O2(g) mc001-1. Jpg 12CO2(g) 6H2O

Andrei [34K]

The enthalpy of combustion of 1 mole of benzene is 3169 kJ/mol .

The first step in answering this question is to obtain the balanced thermochemical equation of the reaction. The thermochemical equation shows the amount of heat lost or gained.

The thermochemical equation for the combustion of benzene is;

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔrH° = -3169 kJ/mol

We can see that 1 mole of benzene releases about 3169 kJ/mol of heat.

Learn more: brainly.com/question/13164491

8 0

2 years ago