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Nastasia [14]
2 years ago
9

No link or Files plz i need help with this one i been stuck on it for a long time

Chemistry
2 answers:
mina [271]2 years ago
5 0

Answer:

The particles in a solid are tightly packed and locked in place. Although we cannot see it or feel it, the particles are moving or vibrating in place. 

kupik [55]2 years ago
4 0

Answer:

molecules in a solid are tightly packed together and vibrate about their fixed positions.

Explanation:

there is very little movement between molecules in a solid since there is not much space between the molecules, hence the slight vibrations.

i hope this helps! :D

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We discussed the different types of intermolecular forces in this lesson. Which type would you expect to find in CO2?
g100num [7]

Answer:

Dispersion forces.

Explanation:

CO2 contains dispersion forces, and covalent bonds. It is a linear molecule, and the bond angle of O-C-O is 180 degree. O is more electronegative than C, the C-O contains polar bond with the having negative end pointing towards the O.

CO contains two C-O bonds. They cancel each other out because of the dipoles point in opposite directions. Although, CO2 contains polar bonds, it is known as a nonpolar molecule. So, the only intramolecular forces which CO2 having are London dispersion forces.

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3 years ago
How can a short-term environmental change, such as a drought or a flood, affect organisms?
viktelen [127]

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it can affect things by drastically chagning the way that organisms opareate such as the eco systems, the health of the land the flood or drought is on and etc.

Explanation:

hope this helps!

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2 years ago
What is the bond energy required to break one mole of carbon-carbon bonds​
ArbitrLikvidat [17]

Answer:

<h2><u><em>100 kcal of bond energy</em></u></h2>

<u><em></em></u>

8 0
3 years ago
Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:
Andru [333]

Answer:

gde

Explanation:

We are attempting to synthesize 1-butyne from 1-chlorobutane. Since 1-chlorobutane is a primary alkyl halide, 1-butene is formed when 1-chlorobutane is reacted with a bulky base such as t -BuOK or t -BuOH in presence of strong heat. This is an E2 reaction.

Secondly, the 1-butene is reacted with bromine in carbon tetrachloride. The vicinal dihalide (1,2-dibromobutane) is formed. This can now undergo further elimination reactions in the presence of sodamide and strong heat to yield 1-butyne which is the desired product. These reactions involve the elimination of the first HBr molecule to give an alkenyl bromide. A second elimination now gives the terminal alkyne.

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3 years ago
Stained glass is homogeneous heterogeneous.​
Serjik [45]

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6 0
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