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Dmitrij [34]
3 years ago
7

Which equation uses the distributive property to show 3 × 47 = 141? A) 3 + (40 × 7) = 141 B) 3 × (40 × 7) = 141 C) 3 + (40 + 7)

= 141 D) 3 × (40 + 7) = 141
Mathematics
2 answers:
navik [9.2K]3 years ago
6 0

Answer:

D) 3 × (40 + 7) = 141

Step-by-step explanation:

(3 × 40 = 120) + (3 × 7 = 21) = 141

Softa [21]3 years ago
5 0

Answer:

D)

Step-by-step explanation:

D) 3 × (40 + 7) = 141

3 × 47 = 141

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OverLord2011 [107]
It is 8. Because 80×10=800
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4 years ago
The proof that AMNS AQNS is shown.
FrozenT [24]

Answer:

The answer is "MS and QS".

Step-by-step explanation:

Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.

As NR and MQ bisect each other at S

⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e   MS=SQ

In ΔMNS and ΔQNS

MN=QN       (∵ MNQ is isosceles triangle)

∠NMS=∠NQS     (∵ MNQ is isosceles triangle)

MS=SQ         (Given)

By SAS rule, ΔMNS ≅ ΔQNS.

Hence, segments MS and SQ are therefore congruent by the definition of bisector.

The correct option is MS and QS

3 0
3 years ago
The graph of line is shown below. Yes
Elina [12.6K]

Answer:

where is the graph??

Step-by-step explanation:

3 0
3 years ago
Based on the figure, which pair of triangles is congruent by the Side Angle Side Postulate?
Lapatulllka [165]

Answer: Triangle ABC and Triangle ECD


Step-by-step explanation:

In Triangle ABC and Triangle ECD

BD=CD and AD=ED [given in the figure]

∠BDA=∠EDC  [Vertically opposite angles are equal]

⇒ΔABC ≅ ΔECD [By SAS postulate]

SAS postulate or Side Angle Side postulate tells that if two sides and their included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

5 0
4 years ago
Read 2 more answers
Random samples of size 64 are taken from an infinite population whose mean and standard deviation are 24 and 6.4, respectively.
umka2103 [35]

Answer:

Mean 24, standard error 0.8

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation, also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 24, \sigma = 6.4, n = 64

What are the mean and the standard error of the sample mean?

By the Central Limit Theorem, mean 24 and standard error s = \frac{6.4}{\sqrt{64}} = 0.8

7 0
3 years ago
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