3 years ago

Which equation represents a direct variation? What is the constant of variation?

Mathematics

1 answer:

V125BC [204]3 years ago

7 0

The answer is C

The constant is -3

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Help me with this pleaseeeeeeeeeee

11Alexandr11 [23.1K]

Answer:

C (-3,5)

Step-by-step explanation:

hope this helps!

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3 years ago

Use the slope formula to find the slope of the line through the points (−1,−2) and (9,−10)

eimsori [14]

Answer:

-4/5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-10-(-2))/(9-(-1))

m=(-10+2)/(9+1)

m=-8/10

simplify

m=-4/5

4 0

3 years ago

If AB is parallel to CD, which statement must be true

Contact [7]

AB and CD do not intersect.

HOPE it helps!!!!!!

8 0

4 years ago

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Convert the general form of the circle given into standard form.

Semmy [17]

$The\ standard\ form\ of\ the\ circle:\\\\(x-a)^2+(y-b)^2=r^2\\\\where\\(a;\ b)\ are\ the\ coordinates\ of\ a\ center\ of\ the\ circle\\r\ is\ a\ radius\ of\ the\ circle\\------------------------$

$2x^2+2y^2-20x-8y+50=0\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2+y^2-10x-4y+25=0\\\\x^2-10x+y^2-4y=-25\\\\x^2-2x\cdot5+y^2-2y\cdot2=-25\\\\\underbrace{x^2-2x\cdot5+5^2}_{(*)}-5^2+\underbrace{y^2-2y\cdot2+2^2}_{(*)}-2^2=-25\\(x-5)^2-25+(y-2)^2-4=-25\\\\(x-5)^2+(y-2)^2-29=-25\\\\(x-5)^2+(y-2)^2=-25+29$

$\boxed{(x-5)^2+(y-2)^2=4}\\\\the\ center:(5;\ 2)\\the\ radius:r=\sqrt4=2$

$(*)\ (a-b)^2=a^2-2ab+b^2$

8 0

4 years ago

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Wat is 1 plas 1? I reeeely want know

Hoochie [10]

Answer:

Step-by-step explanation:

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4 years ago

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