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2 years ago

9

4.

1 answer:

Mashutka [201]2 years ago

3 0

Answer: 13 minutes

Step-by-step explanation:

( 0 + 2 + 10 + 8 + 20 + 12 + 30 + 7 + 40 + 1)/10 = 130/10 = 13

Hope this helps!

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julia spends2.25 on gas for her lawn mower.she earns 15.00 mowing her neighbors yard.what is julias profit but i just need to kn

Effectus [21]

The would be even and I assume you have the answer

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3 years ago

Someone please help asap, I will mark as brainliest. Thank you!!

defon

Answer:

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Step-by-step explanation:

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2 years ago

What is the value of X?

forsale [732]

Answer:

The horizontal value in a pair of coordinates: how far along the point is. The X Coordinate is always written first in an ordered pair of coordinates (x,y), such as (12,5). In this example, the value "12" is the X Coordinate. Also called "Abscissa"

Step-by-step explanation:

hope this helps sorry if it didn’t

7 0

3 years ago

PLEASE HELP ASAP (8)/(27) a^(15) cube of a monomial

vagabundo [1.1K]

Answer:

2/3a^5

Step-by-step explanation:

we know that 2/7x2/7x2/7 = 8/27

a^15 cube will be a^5

because we know (2^3)^2 = 2^6

so (a^5)^3 = a^15

2/3a^5

4 0

3 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

3 years ago