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3 years ago

A car is reduced by 20% in price to $40,000. What was the original price?

Mathematics

2 answers:

VikaD [51]3 years ago

8 0

48000 i think i might have missed a step

yaroslaw [1]3 years ago

5 0

$20\% \times 40000$

$= 8000$

$40000 + 8000$

$48000$

The original price was $48,000.

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Find x?<br> In 3x - In(x - 4) = ln(2x - 1) +ln3

earnstyle [38]

Answer:

$x = \displaystyle \frac{5 + \sqrt{17}}{2}$ .

Step-by-step explanation:

Because $3\, x$ is found in the input to a logarithm function in the original equation, it must be true that $3\, x > 0$ . Therefore, $x > 0$ .

Similarly, because $(x - 4)$ and $(2\, x - 1)$ are two other inputs to the logarithm function in the original equation, they should also be positive. Therefore, $x > 4$ .

Let $a$ and $b$ represent two positive numbers (that is: $a > 0$ and $b > 0$ .) The following are two properties of logarithm:

$\displaystyle \ln (a) + \ln(b) = \ln\left(a \cdot b\right)$ .

$\displaystyle \ln (a) - \ln(b) = \ln\left(\frac{a}{b}\right)$ .

Apply these two properties to rewrite the original equation.

Left-hand side of this equation:

$\begin{aligned}&\ln(3\, x) - \ln(x - 4)= \ln\left(\frac{3\, x}{x -4}\right)\end{aligned}$

Right-hand side of this equation:

$\ln(2\, x- 1) + \ln(3) = \ln\left(3 \left(2\, x - 1\right)\right)$ .

Equate these two expressions:

$\begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned}$ .

The natural logarithm function $\ln$ is one-to-one for all positive inputs. Therefore, for the equality $\begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned}$ to hold, the two inputs to the logarithm function have to be equal and positive. That is:

$\displaystyle \frac{3\ x}{x - 4} = 3\, (2\, x - 1)$ .

Simplify and solve this equation for $x$ :

$x^2 - 5\, x + 2 = 0$ .

There are two real (but not rational) solutions to this quadratic equation: $\displaystyle \frac{5 + \sqrt{17}}{2}$ and $\displaystyle \frac{5 - \sqrt{17}}{2}$ .

However, the second solution, $\displaystyle \frac{5 - \sqrt{17}}{2}$ , is not suitable. The reason is that if $x = \displaystyle \frac{5 - \sqrt{17}}{2}$ , then $(x - 4)$ , one of the inputs to the logarithm function in the original equation, would be smaller than zero. That is not acceptable because the inputs to logarithm functions should be greater than zero.

The only solution that satisfies the requirements would be $\displaystyle \frac{5 + \sqrt{17}}{2}$ .

Therefore, $x = \displaystyle \frac{5 + \sqrt{17}}{2}$ .

7 0

3 years ago

Is the square root of -11.2 a rational number?

Schach [20]

No, it is an imaginary number.
Can't take the square root of a negative number without creating a method termed an imaginary number, which is the square root of -1 which they have used " i " to signify.
Then square root of -11.2 would be written Sqrt(11.2)i. The Sqrt(11.2) = 3.3466
so the answer is 3.3466i

5 0

3 years ago

A store buys 17 sweaters for $255 and sells them for $578. How much profit 1 point

ddd [48]

The answer is 243 is the answer to this question

4 0

2 years ago

Find x and y so that the quadrilateral is a parallelogram.

sergiy2304 [10]

Answer:

Result:

The value of x = 12

The value of y = 21

Step-by-step explanation:

Given

The parallelogram DEFG

DE = 6x-12

FG = 2x+36

EF = 4y

DG = 6y-42

We know that the opposite sides of a parallelogram are equal.

As DE and FG are opposite sides, so

DE = FG

substituting DE = 6x-12 and FG = 2x+36 in the equation

6x-12 = 2x+36

6x-2x = 36+12

simplifying

4x = 48

dividing both sides by 4

4x/4 = 48/4

x = 12

Therefore,

The value of x = 12

Also, EF and DG are opposite sides, so

EF = DG

substituting EF = 4y and DG = 6y-42 in the equation

4y = 6y-42

switching sides

6y-42 = 4y

6y-4y = 42

2y = 42

dividing both sides by 2

2y/2 = 42/2

y = 21

Therefore,

The value of y = 21

Result:

The value of x = 12

The value of y = 21

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3 years ago

Factorize. (x+y)) ^24x^2y^2

irina [24]

Answer:

I guess this is the answer

Step-by-step explanation:

(x + y)²4x²y²

= [2xy(x + y)]²

= (2x²y²)²

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2 years ago