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lapo4ka [179]
3 years ago
13

he gross income of Maurice Vaughn is $785 per week. His deductions are $42.25, FICA tax; $90.33, income tax; 2% state tax; 1% ci

ty tax; and 3% retirement fund. What is his net income for one week? A. $605.32 B. $675.32 C. $628.77 D. $749.77
Mathematics
1 answer:
docker41 [41]3 years ago
3 0

Answer:

A. $605.32

Step-by-step explanation:

The state tax, city tax, and retirement fund add to 6% of Vaughn's wages, or ...

... $785 · 6% = $47.10

Then after subtracting all the deductions, Vaughn's take-home pay is ...

... $785 -42.25 -90.33 -47.10 = $605.32 . . . . matches A

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The Rocky Mountain News (January 24, 1994) indicated that the 20-year mean snowfall in the Denver/Boulder region is 28.76 inches
ycow [4]

Answer:

The p-value of the test is 0.0007 < 0.05, indicating that the the snowfall for the 1993-1994 winters was higher than the previous 20-year average.

Step-by-step explanation:

20-year mean snowfall in the Denver/Boulder region is 28.76 inches. Test if the snowfall for the 1993-1994 winters has higher than the previous 20-year average.

At the null hypothesis, we test if the average was the same, that is, of 28.76 inches. So

H_0: \mu = 28.76

At the alternate hypothesis, we test if the average incresaed, that is, it was higher than 28.76 inches. So

H_1: \mu > 28.76

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

28.76 is tested at the null hypothesis:

This means that \mu = 28.76

Standard deviation of 7.5 inches. However, for the winter of 1993-1994, the average snowfall for a sample of 32 different locations was 33 inches.

This means that \sigma = 7.5, X = 33, n = 32.

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{33 - 28.76}{\frac{7.5}{\sqrt{32}}}

z = 3.2

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 33, which is 1 subtracted by the p-value of z = 3.2. In this question, we consider the standard level \alpha = 0.05.

Looking at the z-table, z = 3.2 has a p-value of 0.9993.

1 - 0.9993 = 0.0007

The p-value of the test is 0.0007 < 0.05, indicating that the the snowfall for the 1993-1994 winters was higher than the previous 20-year average.

5 0
2 years ago
How to sovle <br> (x+1/x)^2
Slav-nsk [51]

(\frac{x + 1}{x} ) ^{2}  \\  =  \frac{ {(x + 1)}^{2} }{ {x}^{2} }  \\  = \frac{ (x + 1)(x + 1) }{ {x}^{2} } \\ = \frac{ {x}^{2}  + 2x + 1}{ {x}^{2} }

Hope you could get an idea from here.

Doubt clarification- use comment section.

4 0
3 years ago
Help!!! Please look at the images. 1 and 2 are the most difficult for me.
Arada [10]
I don’t see the 2 part anywhere?

7 0
3 years ago
A coin weighs 5/6 ounces. Ann picked up 3 of these coins.
JulsSmile [24]
How I’d do it:
5/6 three times makes 15/6. Made into a mixed fraction is 2 3/6, which in its simplest form is 2 1/2.
When converted to ounces, assuming that 6/6 is one complete ounce, then you get 2.5 ounces.
The total weight she picked up is 2.5 ounces.
7 0
3 years ago
The perimeter of a triangle is 37. One side of triangle is one foot longer than the second side. The third side is tgree feet lo
disa [49]

Answer:

First: 12 feet

Second: 11 feet

Third: 14 feet

Step-by-step explanation:

Let the second side of the traingle be x

First side of the triangle= x+1

Third side of the triangle= x+3

x+x+1+x+3 = 37

3x+4 = 37

3x = 37-4

3x = 33

x = 11

First side of the triangle= (11)+1

= 12

Second side of the triangle= 11

Third side of the triangle= (11)+3

= 14

5 0
3 years ago
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