Answer:
12 bags of sand
Step-by-step explanation:
The minimum number of sand to fill the sandbox = 30 cubic feet
The volume or quantity of sand per bag is = 2.5 cubic feet
The minimum number of bags needed to fill the sandbox = 30 / 2.5 = <u>12 bags</u>
Fraction- 3/10
decimal- 0.30
percent- 30%
check the picture below.
so, the rocket will come back to the ground when h(t) = 0, thus
![\bf h(t)=-3t^2+12t\implies \stackrel{h(t)}{0}=-3t^2+12t\implies 0=-3t(t-4)\\\\[-0.35em]~\dotfill\\\\0=-3t\implies 0=t\impliedby \textit{0 seconds when it took off from the ground}\\\\[-0.35em]~\dotfill\\\\0=t-4\implies 4=t\impliedby \textit{4 seconds later, it came back down}](https://tex.z-dn.net/?f=%5Cbf%20h%28t%29%3D-3t%5E2%2B12t%5Cimplies%20%5Cstackrel%7Bh%28t%29%7D%7B0%7D%3D-3t%5E2%2B12t%5Cimplies%200%3D-3t%28t-4%29%5C%5C%5C%5C%5B-0.35em%5D~%5Cdotfill%5C%5C%5C%5C0%3D-3t%5Cimplies%200%3Dt%5Cimpliedby%20%5Ctextit%7B0%20seconds%20when%20it%20took%20off%20from%20the%20ground%7D%5C%5C%5C%5C%5B-0.35em%5D~%5Cdotfill%5C%5C%5C%5C0%3Dt-4%5Cimplies%204%3Dt%5Cimpliedby%20%5Ctextit%7B4%20seconds%20later%2C%20it%20came%20back%20down%7D)
Answer:
First city: $5,500
Second city: $5,000
Step-by-step explanation:
Let's define x as the hotel price in the first city and y the hotel price in the second city. We can start with this equation:
y = x - 500 (The hotel before tax in the 2nd city was $500 lower than in the 1st.)
Then we can say
0.065x + 0.045y = 582.50 (the sum of the tax amounts were $582.50)
We place the value of y from the first equation in the second equation:
0.065x + 0.045 (x - 500) = 582.50
0.065x + 0.045x - 22.50 = 582.50 (simplifying and adding 22.5 on each side)...
0.11x = 605
x = 5,500
The cost of the first hotel was $5,500
Thus, the cost of the second hotel was $5,000 (x - 500)
The answer is D) They do not intersect and are not coplanar.
Hope this helps ;)
