The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
Answer:
True
Explanation:
Capsular hydrostatic pressure (CHP) is a back-pressure that opposes filtration. As the filtrate is forced into the capsular space, it meets 2 forms of resistance: the wall of the capsule and the fluid that has already filled the renal tubule.
This pressure drives fluid out of the capillary (i.e., filtration), and is highest at the arteriolar end of the capillary and lowest at the venular end.
QUESTION:-
What is the maximum number of electrons that can be placed in the first shell/energy level?
A. 1
B. 8
C. 2
D. 18
Answer:
C. 2
The first shell, closest to the nucleus and with the lowest-energy electrons, is shell 1. This first shell has only one subshell (labeled 1s) and can hold a maximum of 2 electrons