By <em>direct</em> substitution and simplification, the <em>trigonometric</em> function z = cos (2 · x + 3 · y) represents a solution of the <em>partial differential</em> equation
.
<h3>How to analyze a differential equation</h3>
<em>Differential</em> equations are expressions that involve derivatives. In this question we must prove that a given expression is a solution of a <em>differential</em> equation, that is, substituting the variables and see if the equivalence is conserved.
If we know that
and
, then we conclude that:





By <em>direct</em> substitution and simplification, the <em>trigonometric</em> function z = cos (2 · x + 3 · y) represents a solution of the <em>partial differential</em> equation
.
To learn more on differential equations: brainly.com/question/14620493
#SPJ1
4x + 1 → C
(f + g)(x) = f(x) + g(x) = 3x - 1 + x + 2 = 4x + 1
Answer:
A = 1863
Step-by-step explanation:
There are a few ways you could do this but I will do the one I know best.
Keep in mind the area is the L(enght x W(idth) = A(rea)
There are two long rectangles if you cut off the square in the middle so find the area of those two first.
31 x 23 = 713
713 x 2 = 1426 (Did this to get the area for both of them.
Now find the area of the square.
23 x 19 = 437
The you would add them all up together to get 1426 + 437 = 1863
Hope this helps :)
Answer:
15
Step-by-step explanation: