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hichkok12 [17]
3 years ago
13

The weight of laboratory mice follows a normal distribution, with a mean of 0.68 ounce and a standard deviation of 0.02 ounce. W

hat percentage of the mice weigh between 0.62 ounce and 0.74 ounce?
A.99.7%
B.95%
C.68%
D.47.5%
E.34%
Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0
The answer is letter D
Soloha48 [4]3 years ago
6 0

Answer:

A.99.7%

Step-by-step explanation:

Calculate each z-score.

z = (x − μ) / σ

z = (0.74 − 0.68) / 0.02

z = 3

z = (x − μ) / σ

z = (0.62 − 0.68) / 0.02

z = -3

You can use a z-score table, or use the empirical rule.

P(-3 < z < 3) = 99.7%.

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What three points are solutions to 2x-y =4
DochEvi [55]

Answer:

Attached file

Step-by-step explanation:

5 0
2 years ago
Please help me please
Murrr4er [49]

The volume of cone B will be 6 cubic units.

<h3>What is the volume of the cone?</h3>

Let h be the height of the cone and A be the base area of the cone.

Then the volume of the cone will be

Volume = (1/3) × A × h

Consider cone A and cone B.

The bases of the cones are congruent.

The height of cone A is 4 times larger than the height of cone B.

\rm h_a = 4h_b

The volume of cone A is 24.

24 = (1/3) Ahₐ

Then the volume of the cone B will be

\rm V = (1/3)Ah_b

Simplify the expression, then the volume will be

V = 1/4 x (1/3)Ahₐ

V = 1/4 x 24

V = 6 cubic units

The volume of cone B will be 6 cubic units.

More about the volume of the cone link is given below.

brainly.com/question/1984638

#SPJ1

4 0
1 year ago
What is the volume of a cone with a base radius of 5 m and a height of 12 m
dolphi86 [110]
Volume of a cone = [(pi)r^2(h)]:3 = [3.14 (25m^2)(12m)]:3 = 314in^3.
7 0
2 years ago
What is another word for grouping
Whitepunk [10]
Another word for grouping is : Combine.
6 0
3 years ago
Not sure if I got it right...I know it is one of the first 2.
e-lub [12.9K]

Answer:

Step-by-step explanation:

-6x^2 + x -3 + 2x + 4

________________________

x^2 + 9

-6x^2 + 3x + 1

__________

  x^2 + 9

the solution is the first one

3 0
3 years ago
Read 2 more answers
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