Does anyone know how to do 15 and 16?????

Mathematics

2 answers:

Julli [10]2 years ago

3 0

This is how you answer number 15 and 16

Ber [7]2 years ago

3 0

ANSWERS- 15.) the second part would be 46.25 i don’t know the first part so sorry though

16.) x=33.3 and 3x+10=57.3

Idk if any of these are right though I haven’t done this in a long time sorry if I made mistakes.
STEPS-
You would find out the measure of the type of line which would be 180 since it’s straight. Then you would solve it algebraically so you would do 4x-5=180, add 5 to both sides (5 would cancel out & 180 would be 185) the divide 185 by 4x and you would get x = 46.25. Sorry I don’t know the other equation for 15.

For 16.) you would turn the equation into 3x-10=90 since it’s a 90 degree angle. Add 10 to both sides so that they cancel each other out then add 10 to 90 and then you should get 100. Now your equation should look like this 3x=100. Next do 100➗3x= 33.3. Now your answer is x=33.3 and the second part would be 90-33.3= 57.3.

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2.2x+3y=15.25 4.6x+2.1y=18.325 USING ELIMINATION SHOW WORK PLEASE

Artist 52 [7]

-4.6(2.2x+3y=15.25) = -10.12x - 13.8y = -70.15

2.2(4.6x+2.1y=18.325) = 10.12x - 4.62y = 40.315

simplify

-4.62y = -29.835

divide both sides by -4.62 to isolate y

y= 6.46

2.2x + 3 (6.46) = 15.25

2.2x + 19.38 = 15.25

subtract 19.38 to both sides

2.2x = -4.3

divide 2.2 to both sides

x= -1.95

I hope that this helped :)

4 0

2 years ago

47 1/2 of what number is 190

Grace [21]

$47 \frac{1}{2} \cdot x=190\\ \\ \frac{47\cdot2+1}{2} \cdotx=190\\ \\ \frac{95}{2} \cdot x=190\ /\cdot \frac{2}{95} \\\\x= \frac{190}{1} \cdot \frac{2}{95}\\ \\x=2\cdot2\\ \\x=4$

3 0

3 years ago

Read 2 more answers

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

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We suppose that tree diameters are normally distributed with mean 8.8 inches and standard deviation 2.8 inches.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

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