Answer:
Should be 4.0(Not sure tho. my thought process is complicated but to me it makes sense)
Step-by-step explanation:
If y=10 and x =2.5, if y were to = 20, then x would equal 5. so you take that ratio, and say 6 is 3/5's the way to 10, so you also divide 2.5 by 3/5
you get 1.5, you add that to x already and you get 4.0
so if y=16, x should =4.0
<h2>
Answer: A. Both are rational.</h2>
Step-by-step explanation:
Although both expressions have square roots, the result of each square root is an integer, which can be expressed as a fraction.
In this sense:
Rational numbers are all numbers that can be represented as the quotient (division) of two integer numbers. This means they can be represented as a fraction in which the denominator is nonzero.
If we solve both expressions, we will be able to see that the result is an integer that can be expressed as a fraction with two integers:
The result is an integer

The result is an integer

Answer:
side b= 11.489
Step-by-step explanation:
well I'm doing the exact same lesson currently and I just did the test on this exact question soo yeahh
Answer:
a. dQ/dt = -kQ
b. 
c. k = 0.178
d. Q = 1.063 mg
Step-by-step explanation:
a) Write a differential equation for the quantity Q of hydrocodone bitartrate in the body at time t, in hours, since the drug was fully absorbed.
Let Q be the quantity of drug left in the body.
Since the rate of decrease of the quantity of drug -dQ/dt is directly proportional to the quantity of drug left, Q then
-dQ/dt ∝ Q
-dQ/dt = kQ
dQ/dt = -kQ
This is the required differential equation.
b) Solve your differential equation, assuming that at the patient has just absorbed the full 9 mg dose of the drug.
with t = 0, Q(0) = 9 mg
dQ/dt = -kQ
separating the variables, we have
dQ/Q = -kdt
Integrating we have
∫dQ/Q = ∫-kdt
㏑Q = -kt + c

when t = 0, Q = 9

So, 
c) Use the half-life to find the constant of proportionality k.
At half-life, Q = 9/2 = 4.5 mg and t = 3.9 hours
So,

taking natural logarithm of both sides, we have
d) How much of the 9 mg dose is still in the body after 12 hours?
Since k = 0.178,

when t = 12 hours,
