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pantera1 [17]
3 years ago
7

4. Duane and Roberto joined a rock-a-thon

Mathematics
2 answers:
KonstantinChe [14]3 years ago
4 0

Answer:

Roberto rocked 3 hours longer than Duane.

-BARSIC- [3]3 years ago
4 0

Answer:

roberto rocked for 3 more hours

Step-by-step explanation:

13-10=3

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What is the measure of \angle 1?, What is the measure of \angle 2?, What is the measure of \angle 4? and What is the measure of
mote1985 [20]

Answer:

<1  and <6 = 98

<2 and <3 = 139

<4 and <5 = 123

Step-by-step explanation:

82 + 9x - 6 + 6x - 1 = 180

15x + 75 = 180

15x = 105

x = 7

<1:

x + 82 = 180

x = 98

<2:

6x - 1 = 6(7) - 1 = 41

x + 41 = 180

x = 139

<3 = <2 because of vertical angle thm so <3 = 139

<5:

9x - 6 = 9(7) - 6 = 57

x + 57 = 180

x = 123

<4 = 5 because of vertical angle thm

<6 = <1 because of vertical angle thm

8 0
2 years ago
PLEASE HELP ME WITH THIS IM BEGGING (35 POINTS) Pleaseeeeeee!<br> I WILL MAKE YOU THE BRAINLIEST
Sergio [31]
1) given
2) definition of linear pair
3) definition of linear pair and supplementary
4) definition of supplementary supplementary angles add to 180
5) the measure of angle one plus the measure of angle 2 plus the measure of angle 3 equals 180
6) substitution in lines 4 and 5
7) the measure of angle one plus the measure of angle 2 equals measure of angle 4 by algebra and simplification
8 0
3 years ago
The measure of angle B is 839, and the measure of angle C is 420.
Usimov [2.4K]

Answer: C. 55 degrees

8 0
3 years ago
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa
gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4  | red dice) = \dfrac{1}{6}

P (4 | green dice) = \dfrac{3}{6} =\dfrac{1}{2}

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = \dfrac{1}{2}

The probability of two 1's and two 4's in the first dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^4

= \dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4

= 6 \times ( \dfrac{1}{6})^4

= (\dfrac{1}{6})^3

= \dfrac{1}{216}

The probability of two 1's and two 4's in the second  dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^2  \times  \begin {pmatrix} \dfrac{3}{6}  \end {pmatrix}  ^2

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= 6 \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= ( \dfrac{1}{6}) \times  ( \dfrac{3}{6})^2

= \dfrac{9}{216}

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = \dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}

The probability of two 1's and two 4's in both die = \dfrac{1}{432}  + \dfrac{1}{48}

The probability of two 1's and two 4's in both die = \dfrac{5}{216}

By applying  Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's )  = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's )  = \dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}

P(second die (green) | two 1's and two 4's )  = \dfrac{0.5 \times 0.04166666667}{0.02314814815}

P(second die (green) | two 1's and two 4's )  = 0.9

Thus; the probability the die chosen was green is 0.9

8 0
3 years ago
Find all of the zeros of the function and write the polynomial as the product of linear factors.
Tomtit [17]

Answer:

(x+6i)(x-6i)(x+1)

So the zeroes are 6i, -6i, -1

Step-by-step explanation:

Factor by grouping

h(x) = x^2(x+1) + 36(x+1)

h(x) = (x^2+36)(x+1)

3 0
3 years ago
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