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Usimov [2.4K]
3 years ago
9

Rhombus LMNO is shown with its diagonals.

Mathematics
2 answers:
KatRina [158]3 years ago
7 0

Answer:

68

Step-by-step explanation:

andrew11 [14]3 years ago
3 0

Answer:

The measure of angle LMN is 68° ⇒ the last answer

Step-by-step explanation:

* Lets revise the properties of the rhombus

- The rhombus has 4 equal sides in length

- Every two opposite angles are equal in measure

- Every two adjacent angles are supplementary (their sum = 180°)

- The two diagonals bisect each other

- The two diagonals perpendicular to each other

- The two diagonals bisect the vertices angles

* Lets solve the problem

∵ LMNO is a rhombus

∴ ∠LMN and ∠MNO are adjacent angles

∴ ∠LMN and ∠MNO are supplementary

∴ m∠LMN + ∠MNO = 180°

∵ m∠MNO = 112°

∴ m∠LMN + 112° = 180° ⇒ subtract 112 from both sides

∴ m∠LMN = 68°

* The measure of angle LMN is 68°

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Answer:

3:5 <em>the colon is needed to represent the ratio</em>

Step-by-step explanation:

r = 10

g = 4

y = 30 - 14 = 6

y = 6

so ratio of total balls is 10:4:6

and ratio of y:r is

6:10

simply by dividing by 2

3:5

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Compare 3.14 to 31.4 which is greater or least equal
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Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From
maksim [4K]

Answer:

The 95% CI for the difference of means is:

-155.45 \leq \mu_1-\mu_2 \leq -44.55

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size:  4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

M_d=M_1-M_2=200-300=-100

The standard deviation can be estimated as:

\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45

The degrees of freedom are:

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The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

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3 years ago
Anyone know how to do this? will give brainlest! if you cant help, have a great day!!!
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