1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
solong [7]
3 years ago
14

Please help

Mathematics
1 answer:
ElenaW [278]3 years ago
5 0

Answer: 3.61km or √13

Step-by-step explanation:

Given Data:

Sides of hexagon = 2km each

Distance walked by Ama = 5km

Therefore;

Let Ama starting position be the origin.

With this She would travel along two edges and then go halfway along a third.

Her new x- coordinate would be

= 1 + 2 + 1/2 = 7/2

Because she travels a distance of 5km which translates to 2 and half side of the Hexagon

= 2*1/2

= 1km. On her x-coordinates

For her y-coordinate we use same principles as x-coordinates

= √3 + 0 - √3/2

= √3/2

Therefore her distance walked

= √ ( (7/2)^2 + (√ 3/2)^2 )

= √ ( 49/4 + 3/4 )

= √ 13

= 3.61km

You might be interested in
What’s the answer to this?
inna [77]

Since the triangle is equilateral, all its angles are equal to 60°

AO is the bisector⇒∠OAD = 30°

AO is the hypotenuse, ∠OAD = 30°⇒

OD=5*2=10m

By the Pythagorean theorem

10^2=AD^2+5^2\\AD=\sqrt{100-25} \\AD=\sqrt{75}

AC=AD+DC=2\sqrt{75}=10\sqrt{3}

S=\frac{a^2\sqrt{3} }{4}

S=\frac{(10\sqrt{3})^2\sqrt{3}  }{4} =\frac{300\sqrt{3} }{4} =75\sqrt{3} m^2

Answer: A) S=75\sqrt{3}m²

P.S. Hello from Russia and sorry for my bad english :^)

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=1%2F2x%5E3%20%2B%20x%20-7%20%3D%20-3%5Csqrt%7Bx%7D%20%20-1" id="TexFormula1" title="1/2x^3 + x
Margaret [11]

Answer:

  none of the above

Step-by-step explanation:

The problem as written cannot have any of the solutions offered.

For any of those choices, the right side expression will be irrational. The left side expression will be rational for any rational value of x, so cannot be equal to the right-side expression.

The solution is an irrational number near ...

  x ≈ 1.33682898582

5 0
3 years ago
What is the answer to the question 0.4 times 100
Lunna [17]
The answer is forty move the decimel by teo places
8 0
3 years ago
Read 2 more answers
SOLVE what is J<br> 3j + 4 = 10<br> J =
tigry1 [53]

Answer: The answer is 2

Step-by-step explanation:

3j + 4 = 10  J = 2

3x2=6

6+4= 10

6 0
1 year ago
Read 2 more answers
Sarah and Bryan went shopping and spent a total of $47.50 Bry an spent $15.50 less than what Sarah spent how much did bryan spen
Bogdan [553]
Since Bryan spent $15.50 less than Sarah, you would start by dividing the total amount they spent together in half.

$47.50 ÷ 2 = $23.75

Then you would take Bryan's 1/2 of the total and subtract $15.50.

$23.75 - $15.50 = $8.25

So, it looks like Bryan spent $8.25.

Check step:

If you add it all back together:

Sarah + Sarah Bryan = Total
$23.75 + $15.50 + $8.25 = $47.50
8 0
3 years ago
Other questions:
  • Which of the following expressions is the conjugate of a complex number with 2 as the real part and 3i as the imaginary part?
    7·2 answers
  • Choose the mixed number that has not been reduced to simplest form.
    15·1 answer
  • A certain company's main source of income is selling cloth bracelets. The company's annual profit (in thousands of dollars) as a
    15·1 answer
  • A line that has a positive x-intercept value and a negative y-intercept value has what type of slope?
    13·1 answer
  • Find the range of 5,3,1,1,3,3,4,4,4,1,1,4,2,2,5,5,5,2,5,5​
    6·1 answer
  • X<br>ax^2+bx+c=0 proof <br>​
    10·1 answer
  • A truck is painting Traffic lines along a highway the truck paints 8 miles of lines in 3 hours at the rate how many miles can a
    9·1 answer
  • Find the LCM of 2,10,and 6
    8·1 answer
  • M is the midpoint of CD. Given the coordinates of one endpoint C(10,-5) and the midpoint M(4, 0), find the coordinates of the ot
    11·1 answer
  • Please help me...asap
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!