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solong [7]
3 years ago
14

Please help

Mathematics
1 answer:
ElenaW [278]3 years ago
5 0

Answer: 3.61km or √13

Step-by-step explanation:

Given Data:

Sides of hexagon = 2km each

Distance walked by Ama = 5km

Therefore;

Let Ama starting position be the origin.

With this She would travel along two edges and then go halfway along a third.

Her new x- coordinate would be

= 1 + 2 + 1/2 = 7/2

Because she travels a distance of 5km which translates to 2 and half side of the Hexagon

= 2*1/2

= 1km. On her x-coordinates

For her y-coordinate we use same principles as x-coordinates

= √3 + 0 - √3/2

= √3/2

Therefore her distance walked

= √ ( (7/2)^2 + (√ 3/2)^2 )

= √ ( 49/4 + 3/4 )

= √ 13

= 3.61km

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amm1812
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4 years ago
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Answer:

\dfrac{14}{29}

Step-by-step explanation:

Let <em>P(A) </em>be the probability that goggle of type A is manufactured

<em>P(B) </em>be the probability that goggle of type B is manufactured

<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

<em>P(A)</em> = 30%

<em>P(B)</em> = 70%

<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

P(A \cap E) will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

P(B \cap E) will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

P(E \cap A) = P(A) \times P(E/A)

P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%

P(E \cap B) = P(B) \times P(E/B)

P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%

P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%

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P(B/E) = \dfrac{P(E \cap B)}{P(E)}

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stiv31 [10]
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