D=√(1.5)(1.4)
d= √6
d= 2.44948.....
Rounded to the nearest tenth would be c. 2.4 mi
Answer:
Step-by-step explanation:
we have
we know that
In this problem
substitute in the formula
Answer:
Check the explanation
Step-by-step explanation:
(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n
(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)
Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1
(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite
<span>when p = -24 and q = 4. p/2q= -24/8 = -3 </span>
Answer:
$16,640
Step-by-step explanation:
Tim's total annual wage expense is ...
($8.00 /h)(40 h/wk)(52 wk/yr) = $8×40×52 /yr = $16,640 per year
