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stiv31 [10]
3 years ago
6

Please help me with these questions

Mathematics
1 answer:
Mars2501 [29]3 years ago
6 0

Slope of a Line Passing through two points (x₁ , y₁) and (x₂ , y₂) is given by :

\spadesuit\; Slope(m) = \frac{y_1 - y_2}{x_1 - x_2}

Given Points are (8 , 30) and (18 , 60)

here x₁ = 8 and x₂ = 18 and y₁ = 30 and y₂ = 60

\spadesuit\; Slope(m) = \frac{30 - 60}{8 - 18} = \frac{-30}{-10} = 3

We know that the form of line passing through point (x₀ , y₀) and having slope m is : y - y₀ = m(x - x₀)

Here the line passes through the point (8 , 30)

⇒ x₀ = 8 and y₀ = 30

We found Slope(m) = 3

Substituting all the values in the standard form, We get :

Equation of the line : y - 30 = 3(x - 8)

Let d be the x-intercept of this line

⇒ The line passes through the point (d , 0) as at x-intercept, y-coordinate is zero.

⇒ 0 - 30 = 3(d - 8)

⇒ 3d - 24 = -30

⇒ 3d = -30 + 24

⇒ 3d = -6

⇒ d = -2

⇒ The x - coordinate of the x-intercept of the line is -2

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A group of researchers wants to know whether men are more likely than women to contract a novel coronavirus. They surveyed two r
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Answer:

Test statistic Z= 0.13008 < 1.96 at 0.10 level of significance

null hypothesis is accepted

There is no difference proportion of positive tests among men is different from the proportion of positive tests among women

Step-by-step explanation:

<em>Step(I)</em>:-

Given surveyed two random samples of 390 men and 360 women who were tested

first sample proportion

                    p_{1} = \frac{360}{390} = 0.9230

second sample proportion

                  p_{2} = \frac{47}{52} = 0.9038

Step(ii):-

Null hypothesis : H₀ : There is no difference  proportion of positive tests among men is different from the proportion of positive tests among women

Alternative Hypothesis:-

There is difference between proportion of positive tests among men is different from the proportion of positive tests among women

 

Z = \frac{p_{1}- p_{2} }{\sqrt{PQ(\frac{1}{n_{1} }+\frac{1}{n_{2} }  } }

where

          P = \frac{n_{1}p_{1} +n_{2}  p_{2} }{n_{1}+n_{2}  }

         P =  0.920

Z= \frac{0.9230-0.9038}{\sqrt{0.920 X0.08(\frac{1}{390}+\frac{1}{52}  } )}

Test statistic Z =  0.13008

Level of significance = 0.10

The critical value Z₀.₁₀ = 1.645

Test statistic Z=0.13008 < 1.645 at 0.1 level of significance

Null hypothesis is accepted

There is no difference proportion of positive tests among men is different from the proportion of positive tests among women







7 0
3 years ago
**IF ANYONE CAN DO ALL OF THESE QUESTIONS CORRECTLY AND FAST, YOU WILK BE MARKED BRAINLIEST!!**What is the measure of arc BC?
bixtya [17]

I think the answer is BC= (bc + de)/2

7 0
3 years ago
A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}

The information provided is:

<em>x</em> = number of students who responded as"yes" = 70

<em>n</em> = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

p=\frac{x}{n}

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

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> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0
3 years ago
Read 2 more answers
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IceJOKER [234]

The first letter can be any one of 5.  For each of those . . .
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The fifth letter is the last remaining one.

  Total number of possibilities = (5 x 4 x 3 x 2 x 1)  = 

                                                          <em> 120 ways</em> to line them up.

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4 0
3 years ago
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Galina-37 [17]
Lets compare both equations so we can explain the reason for it, and see it clearly:
<span>y1 = 5x + 1 
</span><span>y2 = 4x + 2
y1 > y2
</span>5x + 1 > 4x + <span>2
</span>To see why that happens we need to solve for x:
5x - 4x > 2 - 1
x > 1
Therefore, the first equation is greater than the second for values of x > 1
6 0
3 years ago
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