'a', 'c', and 'd' are true for any two circles. That's because
ALL circles are similar. You don't need to prove it. The question
is weird.
First one is C,
Second is A
Third is C pretty sure
Fourth is D
10 1/2 =
10/1 + 1/2=
2/2 (10/1) + 1/2=
20/2 + 1/2=
21/2
Answer:
x=(k√x)/(w^2)(cube√z)
x varies directly with square root of y is:
x = k √y
And inversely with the square of w and cube root of s is:
/(w^2)(cube√z)
Now put those together:
x=(k√x)/(w^2)(cube√z)
The formula is:
x=ky/wz but add the specific info like square, roots, or etc
Answer:
done
Step-by-step explanation: