4.3 I believe. That's the answer I got.
Step-by-step explanation:
1. In PQN & SRT.
a. <RST=<QPN (corresponding angle PQllSR)
b. <STR = <PNQ (corresponding angle TRIINQ)
c. TR=QN (Since TN & QN are opp. Side of parallelogram QNTR)
d. .°.PQN~=SRT.
2.PQN=PSOQ+SNO (whole part axiom)
3.SRT = SNO + NTRO(same as above)
4. PQN=SRT (From st. 1d)
or, PS0Q+SNO =SNO + NTRO (Cancellation of SNO)
or, PS0Q=NTRO
or, PSOQ +QOR=NTRO +QOR (Adding QOR on both side)
or, .°.◼️PQRS = ◼️QRTN
Best of luck!!!!.
Happy New Year from MrBillDoesMath!
Answer:
i ^ (2n) = (i^2)^n = (-1)^n = -1 if n is odd and = 1 if n is even
i ^ (2n+1) = i^(2n)* i = -1 * i = -i if n is odd and = 1*i = i if n is even
Not sure if this answers your question but hopefully pushes you n the right direction.
Thank you,
MrB
Answer:
d = (14.75 - (4 × 2.50) ÷ 2
Step-by-step explanation:
the cost of 1 drumstick = d
2.50×4=10.00
14.75-10.00=4.75
4.75÷2=2 3/8
2 3/8 = 2.375
Answer:
1.26 kg.
Step-by-step explanation:
We have been given that Mr. Snow bought 90 grams of Christmas candy for each of his 14 grandchildren. We are asked to find the amount of candy bought by Mr. Snow in kilograms.
First of all, we will find the amount of candy in grams by multiplying 90 grams by 14 as:


We know that 1 kilogram is equal to 1000 grams. To convert 1260 grams into kg, we will divide 1260 by 1000 as:


Therefore, Mr. Snow bought 1.26 kilograms of candy.