Which is equivalent to , and what type of special product is it?
1 answer:
Answer:
<h2>a perfect square trinomial</h2>Step-by-step explanation:
The given expression is
As you can observe this is a binomial expression under a square power. Additionally, this is a special product, which equivalent expression is a perfect square trinomial, because from this square power we get two perfect square and one linear term.
Therefore, the right answer is B.
Let's solve the expression to demonstrate what we said before
As you can observe, the expression is equivalen to a trinomial.
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(See attached formula)
Years = log (total / principal) / n*log(1 + rate/n) where n = compounding periods per year
Years = log (total / principal) / n*log(1 + rate/n)
Rate of .75% = .0625 per month
We'll say we want total = 200 and principal = 100
Years = log (200 / 100) / 12*log(1 + rate/n)
Years = log (2) / 12 * log (1 + .0625/12)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0022560803 </span> </span> </span> <span><span> </span> </span>
Years = <span> <span> 0.3010299957 </span> </span> / <span> <span> <span> 0.0270729635 </span>
Years = </span></span><span><span><span>11.1192110871 </span> </span> </span>
I don't think that's right
The interest rate is REALLY low. (Less than 1%)
Rate = .75 and .0075 when in a formula
Years = log (2) / 12 * log (1 + .0075/12)
Years = log (2) / 12 * log( <span>1.000625</span>)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0002713493 </span> </span> </span>
Years = <span><span><span> <span> 0.3010299957 </span> </span> / 0.0032561912 </span>
</span>Years = <span><span><span>92.4485010892
THAT seems a more likely answer with such a low interest rate.
</span> </span> </span>
Years = log (total / principal) / n*log(1 + rate/n) where n = compounding periods per year
Years = log (total / principal) / n*log(1 + rate/n)
Rate of .75% = .0625 per month
We'll say we want total = 200 and principal = 100
Years = log (200 / 100) / 12*log(1 + rate/n)
Years = log (2) / 12 * log (1 + .0625/12)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0022560803 </span> </span> </span> <span><span> </span> </span>
Years = <span> <span> 0.3010299957 </span> </span> / <span> <span> <span> 0.0270729635 </span>
Years = </span></span><span><span><span>11.1192110871 </span> </span> </span>
I don't think that's right
The interest rate is REALLY low. (Less than 1%)
Rate = .75 and .0075 when in a formula
Years = log (2) / 12 * log (1 + .0075/12)
Years = log (2) / 12 * log( <span>1.000625</span>)
Years = <span> <span> <span> 0.3010299957 </span> </span> </span> / 12 * <span> <span> <span> 0.0002713493 </span> </span> </span>
Years = <span><span><span> <span> 0.3010299957 </span> </span> / 0.0032561912 </span>
</span>Years = <span><span><span>92.4485010892
THAT seems a more likely answer with such a low interest rate.
</span> </span> </span>