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sergejj [24]
3 years ago
9

What is the inverse of the function f(x) = 2x – 10?

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

f⁻¹(x) = (1/2)x +5

Step-by-step explanation:

In y = f(x), swap the variables, then solve for y. The expression you get is f⁻¹(x).

... y = 2x -10

... x = 2y -10 . . . . . . swapped variables

... x +10 = 2y . . . . . add 10

... (1/2)x + 5 = y . . . . divide by 2

... f⁻¹(x) = (1/2)x + 5 . . . . . . rewrite using function notation

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Quadratic equations w complex roots <br> x2 - 6x + 12 = 0
Dmitriy789 [7]

Answer:

x = 3 ± i \sqrt{3}

Step-by-step explanation:

Given

x² - 6x + 12 = 0 ( subtract 12 from both sides )

x² - 6x = - 12

Using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 3)x + 9 = - 12 + 9

(x - 3)² = - 3 ( take the square root of both sides )

x - 3 = ± \sqrt{-3} = ± i \sqrt{3} ( add 3 to both sides )

x = 3 ± i \sqrt{3}

7 0
2 years ago
2x-y=8<br>x+2y=4<br><br>for the system of equation above, what is the value of x+y?​
inysia [295]
2x+10y I thinks that’s the answer mb
3 0
3 years ago
Read 2 more answers
During a Grand Prix car race, the tyres on a car are reduced in mass by 3%. If their mass is 388 kg at the end of the race, what
spayn [35]

Answer:

Their mass at the start was 400 kg.

Step-by-step explanation:

Given:

The tyres on a car during a grand prix race are reduced in mass by 3%. Their mass is 388 kg at the end of the race.

Now, to find the mass at the start.

<u>Let the mass at the start be x.</u>

According to question:

x - 3 \%ofx= 388

⇒x-\frac{3}{100}\times x = 388

⇒x-0.03x =388

⇒0.97x=388

<em>Dividing both sides by 0.97 we get:</em>

⇒x=400

Therefore, their mass at the start was 400 kg.

8 0
3 years ago
What is the equation of the line that passes through the point (-2,0) and has a slople of -2 ​
SCORPION-xisa [38]

Answer:

y= -2x-4

Step-by-step explanation:

(-2,0) = (x_1,y_1) \\ m =  - 2

Substitute values into point slope form

y - y_1 = m(x - x_1) \\ y - 0 =  - 2(x - ( - 2)) \\ y - 0 =  - 2(x + 2) \\ y - 0 =  - 2x - 4

y =  - 2x - 4 + 0 \\ y=  - 2x - 4

6 0
3 years ago
Anyone mind helping me! ( The selected answer was chosen on accident!)
deff fn [24]

Answer:

-x² - 4x + 6

Step-by-step explanation:

(-2x² - 3x + 4) - (-x² + x - 2) =

= -2x² - 3x + 4 + x² - x + 2

= -x² - 4x + 6

4 0
2 years ago
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