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3 years ago

Express 240 as a product of prime factors.

Mathematics

2 answers:

Sholpan [36]3 years ago

6 0

Answer:

240 = 2 x 2 x 2 x 2 x 3 x 5 or 2^4x3x5

Step-by-step explanation:

240

/ \

2 120 (240 = 2 x 120)

/ \

2 60 (120 = 2 x 60)

/ \

2 30 (60 = 30 x 2)

/ \

2 15 (30 = 2 x 15)

/ \

3 5

Juliette [100K]3 years ago

3 0

240

24 10

6 4 5 2

3 2 2 2

you stop when you reach prime numbers

5x3x2x2x2x2= 240

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Find the value of the expression 4a to the fourth power - 2b squared +40 when a =2 and b=7

Tom [10]

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4(32)-2(49)+40
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3 years ago

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Step-by-step explanation:

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3 years ago

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Evaluate the surface integral. s x ds, s is the part of the plane 18x + 9y + z = 18 that lies in the first octant.

IceJOKER [234]

In the first octant, the given plane forms a triangle with vertices corresponding to the plane's intercepts along each axis.

$(x,0,0)\implies 18x+9\cdot0+0=18\implies x=1$
$(0,y,0)\implies 18\cdot0+9y+0=18\implies y=2$
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Now that we know the vertices of the surface $\mathcal S$ , we can parameterize it by

$\mathbf s(u,v)=\langle(1-u)(1-v),2u(1-v),18v\rangle$

where $0\le u\le1$ and $0\le v\le1$ . The surface element is

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=2\sqrt{406}(1-v)\,\mathrm du\,\mathrm dv$

With respect to our parameterization, we have $x(u,v)=(1-u)(1-v)$ , so the surface integral is

$\displaystyle\iint_{\mathcal S}x\,\mathrm dS=2\sqrt{406}\int_{u=0}^{u=1}\int_{v=0}^{v=1}(1-u)(1-v)^2\,\mathrm dv\,\mathrm du=\frac{\sqrt{406}}3$

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3 years ago

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nikdorinn [45]

Answer:

Step-by-step explanation:

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1 year ago

Give the scale factor of Figure B to Figure A.

uysha [10]

The figures are similar.

the side that is 16 on A is similar to the side that measures 4 on figure B

24 is similar to 6

32 is similar to 8

24 is 4 times 6

24 / 6 = 4

32 is 4 times 8

32 / 4 = 4

and 16 is 4 times 4

16 /4 =4

Figure A is 4 times bigger than Figure B. That is your scale factor.

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2 years ago