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IgorLugansk [536]
3 years ago
9

The length of a text messaging conversation is normally distributed with a mean of 2 minutes and a standard deviation of 0.5 min

utes. What is the probability that a conversation lasts longer than 3 minutes? 0.043351 0.063748 0.02275 0.095424
Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0
Given:
μ = 2 min, population mean
σ = 0.5 min, population standard deviation

We want to find P(x>3).

Calculate the z-score
 z= (x-μ)/σ = (3-2)/0.5 = 2

From standard tables, obtain
P(x ≤ 3) = P(z ≤ 2) = 0.9772
Therefore
P(x > 3) = P(z > 2) = 1 - 0.9772 = 0.0228

Answer: 0.02275
jorelis
2 years ago
are you sure?
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Answer:

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8 0
3 years ago
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I need some help with this calculus 1 implicit diffrention problem?
katen-ka-za [31]

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12 + 2y y" + 2(-6x/y)² = 0

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3 years ago
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Anna71 [15]
\sf \frac{4}{20}~\underrightarrow{\sf ~simplify~by~4~~}~\frac{4:4}{20:4} =\boxed{\sf  \frac{1}{5} }
3 0
3 years ago
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vampirchik [111]
A= 1.5 × 10^10




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3 years ago
A museum has a model of an Egyptian pyramid. It has a rectangular base that is 10 feet by 8 feet, with a height of 12 feet.
FrozenT [24]

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