Question

How many moles of nitrogen N are in 71.0g of nitrous oxide , N2O

Answer 1

1.6 moles of N2 in 71g

Answer 2

Answer : The number of moles of nitrogen present in nitrous oxide are 3.22 moles.

Explanation : Given,

Mass of $N_2O$ = 71.0 g

Molar mass of $N_2O$ = 44 g/mole

First we have to calculate the moles of $N_2O$.

$\text{ Moles of }N_2O=\frac{\text{ Mass of }N_2O}{\text{ Molar mass of }N_2O}=\frac{71.0g}{44g/mole}=1.61moles$

Now we have to calculate the moles of nitrogen in nitrous oxide.

In nitrous oxide $N_2O$, there are 2 moles of nitrogen and 1 mole of oxygen.

As, 1 moles of $N_2O$ contains 2 moles of nitrogen

So, 1.61 moles of $N_2O$ contains $1.61\times 2=3.22moles$ of nitrogen

Therefore, the number of moles of nitrogen present in nitrous oxide are 3.22 moles.