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Likurg_2 [28]
3 years ago
8

In this reaction, the chromium is reduced, from Cr6+ to Cr3+, causing a color change in the solution, signaling the endpoint. De

termine the mass percent ethanol in a 40.0 g blood sample, if the sample required 22.6 mL of 0.05 M K2Cr2O7 to react completely with all the ethanol answers
Chemistry
1 answer:
Travka [436]3 years ago
8 0

Answer:

Using the information provided in the question, the percentage by mass of ethanol in the blood is 0.1949%.

Explanation:

The balanced equation for the reaction can be written as:

3CH3CH2OH + 2K2Cr2O7+ 16H+ >>>> 3CH3COOH + 4Cr3+ + 4K+ + 11H2O. This will be used to solve the problem.

The no of moles of K2Cr2O7 used = concentration X volume in dm cube.

= 0.05 X 22.6/1000 = 1.13/1000 = 0.00113 moles of K2Cr2O7 was used.

From the balanced equation above, 3 moles of ethanol will react with 2 moles of K2Cr2O7.

Therefore, 0.00113 X 3/2 moles of ethanol would have been in the blood of the subject = 0.001695 moles of ethanol.

Remember that no of moles = mass/molar mass. Then mass = moles X molar mass.

The molar mass of ethanol is 46g/mole.

Then mass = 0.001695 X 46 = 0.07797gram of Ethanol was in the blood.

Percentage by mass in blood is: 0.07797/40 X 100 = 0.1949%

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