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VLD [36.1K]
3 years ago
6

Elements that have the following qualities: Lustrous, Solid at Room Temperatures, They react and form Basic Compounds, Great con

ductors, High Melting Point, are classified as what?
Chemistry
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

They are classified as METALS.

Explanation:

Elements are simple substances that cannot be chemically broken down into smaller substances. Based on different characteristics, they are classified into 3 namely:

- metals

- non metals and

- metalloid( mainly act as semi- conductor).

METALS are the type of elements that loses electrons to form positive ion, that is, they are electropositive elements. They are distinguished by the following characteristics:

- LUSTROUS: they have the ability to reflect light from its surface.

- At room temperature: Metals are solid are room temperature with the exception of Mercury which is liquid at room temperature.

- They react and form Basic Compounds

- Great conductor: most metals are great conductors of heat and electricity because they possess free electrons.

- Melting Point: they have high melting points.

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Iron is ___<br> A, FE<br> B,CU<br> C,K<br> D, CA
Fiesta28 [93]

<em>Answer:</em>

<em>Ello mate ! the answer is super simple it's option "A" Fe</em>

<em>Explanation:</em>

<em>Iron is a chemical element with symbol</em><em> "Fe"</em><em> and atomic number 26. It is a type of metal, that belongs to the first transition series and group 8 of the periodic table. It is by mass the most common element on Earth, forming much of Earth's outer and inner core.</em>

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3 years ago
How many moles of Ba(NO3)2 are there in 0. 25 L of a 2. 00 M Ba(NO3)2 solution? Use Molarity equals StartFraction moles of solut
ANEK [815]

The moles of barium nitrate in the solution has been 0.5 mol. Thus, the correct option is B.

Molarity has been defined as the moles of substance in a liter of solution. Molarity has been expressed as:

\rm Molarity=\dfrac{Moles}{Volume}

<h3>Computation for moles of Barium nitrate</h3>

The given barium nitrate solution has the volume of 0.25 L.

The molarity of the solution has been 2 M.

Substituting the values for the moles of Barium nitrate

\rm 2=\dfrac{Moles}{0.25}\\&#10; Moles=2\;\times\;0.25\;mol\\&#10;Moles=0.5\;mol

The moles of barium nitrate in the solution has been 0.5 mol. Thus, the correct option is B.

Learn more about molarity, here:

brainly.com/question/12127540

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