I got 2,500 left after 5 years.
10,000*15% = 1,500 or you could do 10,000*.15 = 1,500
That is a loss of 1,500 fish per year.
If you want to think of this as a proportion then you would do
Year/fish lost
1/1,500 = 5/x
X=5*1,500
X=7,500
The population of the fish after 5 years equals
10,000-7,500 = 2,500
So your answer is 2,500 fish are left
Just differentiate <em>G</em> and <em>H</em> :
• d<em>G</em>/d<em>x</em> = d(<em>x</em> ² <em>eˣ </em>)/d<em>x</em> = 2<em>x</em> <em>eˣ</em> + <em>x</em> ² <em>eˣ</em>
so <em>G</em> is not an antiderivative of <em>f</em>.
• d<em>H</em>/d<em>x</em> = d(2<em>x</em> <em>eˣ</em> - 2<em>eˣ</em> ) = (2<em>eˣ</em> + 2<em>x</em> <em>eˣ</em> ) - 2<em>eˣ</em> = 2<em>x</em> <em>eˣ</em> = <em>f(x)</em>
so <em>H</em> is indeed an antiderivative of <em>f</em>.
- From the table showing in the diagram, Let's pick the data in the first row:
Time = 3 hours
Money earned = $45
- The amount of money Carl earns per hour is calculated as:
3 hours = $45
1 hour = ?
Cross Multiply
1 hour x $45 / 3 hours
= $15
- Let's confirm our answer using the data in the last column
Time = 10 hours
Money earned = $150
The amount of money Carl earns per hour is calculated as:
10 hours = $150
1 hour = ?
Cross Multiply
1 hour x $150 / 10 hours
= $15
Therefore, the amount of money Carl earns per hour is $15
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1.40 or 1.4 would be the square root of 2
