distance = speed * time
the first bus speed = x
second bus = x - 12
the sum of distance = 765 miles
first distance = 6x
second distance = 6 (x -12)
6x + 6(x-12) = 765
x + x -12 = 127.5
2x = 139.5
x = 69.75 mi/h which is the faster bus
the second bus speed = 57.75 mi/h
Answer:
20/5 = x /4 x = 80/5 = 16
x - 10 / 39 = 5/15 = 1/3
3x - 30 = 39
3x = 69
x = 23
(2x + 10 ) * 4 = 10 *(x + 3)
8x + 40 = 10x + 30
2x = 10
x = 4.
AE = 2(5) + 10 = 20, hope this helped.
Answer:
Step-by-step explanation:
2.
y=kx
8=-4k
k=-2
so y=-2x
3.
4.
eq. of line is y-5=4(x+2)
Answer:
1.7(12) + 3(-6) = 84 - 18 = 66
Answer:
2x+5
Step-by-step explanation:
Okay so lets first factor 2x^2+15x+25
2*25=50
10+5=15
10*5=15
(x+10/2)(x+5/2)
=(x+5)(2x+5)
we know that the width is x+5 so that means the length has to be 2x+5
