No, because since this decimal doesn't stop, it doesn't count as terminating
Answer:
Step-by-step explanation:
construct a semicircle with center at C and cutting line AB at D and E.
With D and E as centres draw two arcs with same radius cutting at P and Q.
Join P and Q. It is the required perpendicular.
Y = -1/2x - 6......u have a slope of -1/2....u have a y int of -6 or (0,-6)
the x int can be found by subbing in 0 for y and solving for x
0 = -1/2x - 6
1/2x = -6
x = -6 * 2
x = -12.....so ur x int is -12 or (-12,0)
so go ahead and plot ur intercepts.....(0,-6) and (-12,0)...well...u cant really plot ur x axis because ur graph is not big enough....so start at (0,-6)...and I know the slope is -1/2....and u would usually start at (-12,0)...but that is not on the graph....so start at (0.-6)....and go up 1 and to the left 2, plot that point....then up 1 and to the left 2...plot that point......u would eventually cross the x axis at (-12,0).
or u could just go to desmos....its a graphing calculator...and see for urself
Answer:
The height would be 18.99
