Step-by-step explanation:
x = number hours dog walking
y = number hours tutoring
x + y <= 11
6x + 10y >= 80
the solution is the common area below the first line and above the second line.
the first line is above the second line (due to the y-intercept of 11 vs. 8) until the crossing point.
for the crossing point we use the regular equations :
from the first we get
x = 11 - y
using this in the second
6×(11 - y) + 10y = 80
66 - 6y + 10y = 80
4y = 14
y = 14/4 = 7/2 = 3.5
x = 11 - y = 11 - 3.5 = 7.5
so, she has to do at least 3.5 hours tutoring (and then 7.5 hours dog walking) for the minimum of $80 earning, all the way up to the maximum of 11 hours tutoring (and 0 dog walking) for $110 earning.
Answer:
Step-by-step explanation:
x^2 + 3x + 2 = (x+1)(x+2)
x^2 + 4x + 3 = (x+1)(x+3)
LCM = (x+1)(x+2)(x+3) = (x^2 + 3x + 2) (x+3) = x^3 + 6x^2 + 11x + 6
400 reduced by 4 times my age is 116...
400 - 4x = 116
-4x = 116 - 400
-4x = - 284
x = -284/-4
x = 71 <===
Answer:
We conclude that:
h(f(-1)) = -2
∴ option D i.e. -2 is correct.
Step-by-step explanation:
Given
f(x) = 4x² - 1
g(x) = 1/2x + 5
h(x) = 2(x - 4)³
To determine
h(f(-1)) = ?
In order to determine h(f(-1)) first we need to determine f(-1).
substitute x = -1 in the function f(x) = 4x² - 1
f(-1) = 4(-1)² - 1
f(-1) = 4(1) - 1
f(-1) = 4-1
f(-1) = 3
so
h(f(-1)) = h(3)
now substitute h = 3 in the function h(x) = 2(x - 4)³
h(x) = 2(x - 4)³
h(3) = 2(3 - 4)³
h(3) = 2(-1)³
h(3) = 2(-1)
h(3) = -2
Thus,
h(f(-1)) = h(3) = -2
Hence, we conclude that:
h(f(-1)) = -2
∴ option D i.e. -2 is correct.
