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erica [24]
3 years ago
14

6.

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

8

Step-by-step explanation:

10+8-3+5-12=

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Whoch expression is equivalent to -20 - (-4)​
dangina [55]

Answer:

D

Step-by-step explanation:

-(-4)=+4

so it is -20+4

5 0
3 years ago
Read 2 more answers
Given z=f(x,y),x=x(u,v),y=y(u,v), with x(1,3)=2 and y(1,3)=2, calculate zu(1,3) in terms of some of the values given in the tabl
stich3 [128]

The value of zu(1,3) using the data elements represented on the table of values is q + p

<h3>How to solve the calculus expression?</h3>

The given parameters are:

z = f(x, y)

x = x(u, v)

y = y(u, v)

Where

x(1, 3) = 2 and y(1, 3) = 2

To calculate zu(1,3), we make use of:

z_u(1,3) = f_x(x,y) * x_u(1,3) +  f_y(x,y) * y_u(1,3)

The values x(1, 3) = 2 and y(1, 3) = 2 mean that:

(x,y) = (2,2).

So, we have:

z_u(1,3) = f_x(2,2) * x_u(1,3) +  f_y(2,2) * y_u(1,3)

From the table of values, we have:

f_x(2,2) = q

x_u(1,3) = 1

f_y(2,2) = 1

y_u(1,3) = p

So, the equation becomes

z_u(1,3) = q * 1 +  1 * p

Evaluate the product

z_u(1,3) = q + p

Hence, the value of zu(1,3) is q + p

Read more about calculus at:

brainly.com/question/5313449

#SPJ1

3 0
2 years ago
1. Three apples, a, and two peaches, p, sell for $1.25.
Simora [160]

Answer:

$0.25

Step-by-step explanation:

You can use systems of equations to solve this.

3a+2p = 1.25

5a+p = 1.5

Multiply the second equation by 2.

3a+2p = 1.25

10a+2p = 3

Subtract the bottom from the top

-7a= -1.75

Divide by -7

a= 0.25

Each apple is $0.25 (in this case, the peach also costs $0.25)

5 0
3 years ago
9 – 2k = 25 what is k
worty [1.4K]

Answer:

k = - 8

Step-by-step explanation:

Subtract 9 from both sides to get the constants on one side and the variables on the other

9 - 2k = 25

- 2k = 25 - 9

Simplify

- 2k = 16

Divide by -2 on both sides to isolate the variable, then simplify once more.

- 2k/ -2 = 16/ -2

k = 16/ -2

k = -8

8 0
3 years ago
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Help me!! With this until question fifteen thank you
Novay_Z [31]
Look up the.name of the book online with anser sheet I had that same book just find the page
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