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3 years ago

Which of the following tables does NOT define a function?

Mathematics

2 answers:

Mashutka [201]3 years ago

6 0

C. The answer is C since in the y side, there are two '0.' That cannot be possible. Even if it is possible, you can tell that the number are both different for x=0. Therefore, C is the answer.

madreJ [45]3 years ago

5 0

Answer:

Step-by-step explanation:

doesnt define a function

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In order to estimate the mean amount of time computer users spend on the internet each month, how many computer users must be s

levacccp [35]

Answer:

1877 computer users

Step-by-step explanation:

We have that for 95% of confident, the value of z has a value of 1.96 (attached table about it), they also mention the margin of error (E) that is 10 and finally the standard deviation (sd) that has a value of 221.

We apply the following formula:

n = [z * sd / E] ^ 2

replacing:

n = [1.96 * 221/10] ^ 2

n = 1876.27

that is, the minimum sample size is 1877

7 0

3 years ago

Keith earns $37.00 in 4 hours. How much would he earn in 11 hours?

Leona [35]

Answer:

Step-by-step explanation:

37/4= 9.25

9.25*11 =101.75

7 0

3 years ago

Read 2 more answers

I need help on number one

Harman [31]

180=90+50+x
180=140+x
x=180-140=40

X=40

7 0

3 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

3 years ago

The large rectangle below represents one whole.

Sonja [21]

Answer:

40%

Step-by-step explanation:

<h3>so have 5 rectangles in a whole.</h3><h3>we also have 2 shaded potions in that whole which represents 2/5 shaded potions.</h3>

<h3>2/5 in fraction =0.4</h3>

<h3>Now Change 0.4 to percentage by multiplying 0.4 by 100</h3>

<h3>0.4 x 100 = 40</h3><h3>Therefore the percentage represented by the shaded area is 40%</h3><h3> </h3><h3>Hope this helps.</h3><h3>Good luck ✅.</h3>

5 0

2 years ago